Show function seems to be broken

Question

I read the thread How to make the Show function work in this case?. I think I have the same problem as discussed there. But when I try the to evaluate

Show[Plot[x^2, {x, 2, 10}], Plot[1 - x, {x, 1, -10}], 
  PlotRange -> All]

it doesn't work. The output:

.

How can I fix it?

Update: This comes afterClear["*", All];. Clear["*", All]; Show[Plot[x^2, {x, 2, 10}], Plot[1 - x, {x, 1, -10}], PlotRange -> All] makes it failed.

Have you played with $DisplayFunction? What if you evaluate $DisplayFunction = Identity? — Kuba, Jul 15 '16 at 06:04
@Kuba Now I can't reproduce it after restart Mathematica for several times... Why should I evaluate $DisplayFunction = Identity? What's Identity? I have never heard it before. — huangbiubiu, Jul 15 '16 at 06:40
I can not reproduce your problem. I get the expected plot when I evaluate your code with V10.4.1 running on OS X 10.10.2. — m_goldberg, Jul 15 '16 at 06:57
I'm voting to close this question as off-topic because the problem the user is experiencing can not be reproduced by others. — m_goldberg, Jul 15 '16 at 06:58
@m_goldberg I know what I did. Add Clear["*", All]; before the command can reproduce it. I can't see why Claer makes it failed. — huangbiubiu, Jul 15 '16 at 07:10
(5682) may interest you, as well as the documentation for $DisplayFunction — Mr.Wizard, Jul 15 '16 at 07:46

Kuba · Accepted Answer · 2016-07-15T07:39:08.297

4

Clear["*"] clears every symbol found on $ContextPath which is not Protected. So many System` symbols too...

Moreover, unless you want to double clear System`All, Clear["*", All] is made up syntax.

What you probably want is Clear["Global`*"] or ClearAll["Global`*"]

Weren't you warned by:

edited Jul 15 '16 at 07:39

answered Jul 15 '16 at 07:28

Kuba

136,707
13
279
740

1

Ergo, Show appeared to be broken because the OP broke it. – m_goldberg Jul 15 '16 at 07:29

Show function seems to be broken

1 Answers1