Please have a look at below. I need to solve two-coupled equations and plot the results h[2] and theta[2]. I am not sure about the function definition for p01 and p02 which use x as a variable not h[2] and theta[2]. Then I put these p01, p02 inside first, second, etc which use h[2] and theta[2] as argument. I guess that part cause the problem for manipulate..
p01[x_] := 2*h[2]/k*Log[(x - b)/(-b)] + theta[2]/k*x + 1/2;
p02[x_] := 2*h[2]/k*Log[(x - b)/(1 - b)] + theta[2]/k*(x - 1);
first[h[2] _, theta[2] _] := Integrate[p01[x], {x, 0, b}, Assumptions -> 0 < b < 1]
second[h[2] _, theta[2] _] := Integrate[p02[x], {x, b, 1}, Assumptions -> 0 < b < 1]
third[h[2] _, theta[2] _] := Integrate[(x - b)*p01[x], {x, 0, b}, Assumptions -> 0 < b < 1]
fourth[h[2] _, theta[2] _] := Integrate[(x - b)*p02[x], {x, b, 1}, Assumptions -> 0 < b < 1]
Solve[2*M*h[2] == first[h[2] _, theta[2] _] + second[h[2] _, theta[2] _] -
M*g && 2*M*gamma*theta[2] == third[h[2] _, theta[2] _] + fourth[h[2] _,
theta[2] _], {h[2], theta[2]}]
h[0] = k*b*(1 - b);
theta[0] = k*(1 - 2*b);
height[t_] := h[0] + t^2*h[2];
angle[t_] := theta[0] + t^2*theta[2];
Manipulate[
Plot[ h[0] + t^2*h[2], {t, 0, 0.1}, Filling -> filling,
PlotRange -> {0.232, 0.245}], {M, {None, 1, 0.5, 0.2, 0.1, 0}}, {M,
0, 1}, {g, {None, 10, 5, 2, 1, 0.5, 0.1, 0}}, {g, 0, 10},
{b, {None, 1, 0.6, 0.5, 0.3, 0}}, {b, 0, 1},
{gamma, {None, 1, 0.5, 0.2, 0}}, {gamma, 0, 1},
{k, {None, 1, 0.5, 0.2, 0}}, {k, 0, 1},
{filling, {None, 2, 1.5, 1, 0.5,
0, -0.5, -1, -1.5, -2}}, {filling, -2, 2}, SaveDefinitions -> True]
Manipulatescopes its variables, so you have to tell Manipulate that those variables are there, either with the replacement rule trick explained by @feyre, or by redefining your functions to include the variables, i.e.h[2, M_, g_] := ...rather thanh[2, M, g]. – march Oct 13 '16 at 16:37M, g, b, gamma, k. As I usedheight[t_, kappa_, b_, M_, g_, gamma_] insideManipulate, I have below code:Manipulate[ Plot[ height[t_, [Kappa], b, M_, g_, [CapitalGamma]_], {t, 0, 0.1}, Filling -> filling, PlotRange -> .....` However, I do not have any luck.. – Meva Oct 13 '16 at 23:58