Piecewise defining function, Why do i get extra 0 True?

Asked Jan 15 '17 at 12:47

Active Jan 15 '17 at 12:47

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I have included a picture

This happens on every Piecewise function

asked Jan 15 '17 at 12:47

Math Newbie

That's the "default case", which gives the result to be returned if none of your other conditions are satisfied by the argument x. – J. M.'s missing motivation Jan 15 '17 at 12:50
Would it be correct to write {x^2*Cot[x], True} On the last piece ? – Math Newbie Jan 15 '17 at 13:06
Should be fine, yes. – J. M.'s missing motivation Jan 15 '17 at 13:09

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