ReplaceAll with StringContains

Question

I would like to replace lists within a list based on a string pattern with a blank sequence:

list = {{"", "abc"}, {"", "ooobc"}};  
rules = {{_, "abc"} -> "x", {_, ___~~ "bc"}->"y"};  
ReplaceAll[list, rules]
{"x", {"", _ ~~ "ooobc"}}

I would like to replace {"", "ooobc"} with "y". Since I tried from different angles - is there an elegant approach to use ReplaceAll with some kind of StringContainsQ logic?

Edit: One of the comments solves my problem well, so for completeness I add here:
rules = {{_, "abc"} -> "x", {_, _?(StringMatchQ[___ ~~ "bc"])} -> "y"};

What do you want to achieve? Does something like rules = {{_String, _?(StringMatchQ["abc", #] &)} -> "x"}; work for you? — Lukas Lang, Sep 26 '17 at 19:02
I would like to replace based on a StringContains logic, i.e. if a String within any of the sublists contains "bc" as 2nd element, it should be replaced. — Patrick Bernhard, Sep 26 '17 at 19:11
rules = {{_, "abc"} -> "x", {_, x_} /; StringContainsQ[x, "bc"] -> "y"}; like that? — N.J.Evans, Sep 26 '17 at 19:17
Or, if you need something more general than StringContainsQ: rules = {{_, "abc"} -> "x", {_, _?(StringMatchQ[___ ~~ "bc"])} -> "y"}; — Lukas Lang, Sep 26 '17 at 19:19

kglr · Answer 1 · 2017-09-27T09:56:35.777

condition = StringEndsQ["bc"];
rules = {{_, "abc"} -> "x", {_, _?condition} -> "y"};
(* or rules = {{_, "abc"} -> "x", {_, _?(StringEndsQ["bc"])} -> "y"}; *)

ReplaceAll[list, rules]

{"x", "y"}

You can also use StringMatchQ["*bc"] or StringContainsQ["bc"] in place of StringEndsQ["bc"].

Alternatively, you can use Condition (/;) instead of PatternTest (?) :

rules2 = {{_, "abc"} -> "x", {_, x_ /; condition[x]} -> "y"};

ReplaceAll[list, rules2]

{"x", "y"}

ReplaceAll with StringContains

1 Answers1