How to calculate the following integral symbolically with Mathematica:
$$ I = \int_0^\infty \frac{\mathrm{d}x}{(x^2+a^2)(\ln^2x+\pi^2)} $$
where $a>0$ is a real number.
PS: from complex analysis, we can determine it:
$$ I = \frac{2\pi}{(4\ln^2a+\pi^2) \, a} - \frac{1}{a^2+1} $$
Integrate(Mathematica v11.1). So, without providing significant help, it is unlikely it would be able to do it for more general $a$. – QuantumDot Oct 08 '17 at 09:48