If I use an arbitrary function f'[t] inside a definite integral, Mathematica (correctly) refuses to apply the fundamental theorem of calculus, because it doesn't know if f'[t] is continuous.
Is there a way to define an arbitrary function with the assumption that it is continuous, such that the definite integral between a and b evaluates to f[b] - f[a]?
SetAttributes[f, NumericFunction]and then integrate. – Carl Woll Feb 02 '18 at 01:49Attributeto set to makeIntegrateapply the fundamental theorem. Do you know why it was designed like this? – QuantumDot Feb 02 '18 at 16:30