Progress bar / counter for multi-row table with 2 variables

Question

I have a table that takes a long time to calculate because f[x] is quite a complicated function:

Table[f[x], {m, 50, 1000, 50}, {x, 0, 50}]

It would be great to have a progress bar to give some idea of how long the evaluation will take to complete. Ideally, I would also like a counter stating which values of m and x are currently being assessed.

This thread offers a simple progress bar:

Monitor[
 Table[Pause[0.1]; Prime[i], {i, 100}],
  Row[{ProgressIndicator[i, {1, 100}], i}, " "]
]

But I can't figure out how to adapt this for a multi-row table with two variables, or how to produce a counter that tells me what values of m and x are currently being evaluated.

I'd be very grateful for any solutions.

Monitor[ Table[Pause[0.01]; Prime[m x], {m, 50, 1000, 50}, {x, 1, 50}], Grid[{ {"Total progress:", ProgressIndicator[Dynamic[m/1000]]}, {"Current row progress:", ProgressIndicator[Dynamic[x/50]]}, {"{m, x}=", {Dynamic@m, Dynamic@x}} }] ]? — Kuba, May 16 '18 at 19:07

score 2 · Accepted Answer · answered May 16 '18 at 18:30

2

How about a simple method such as this. You can easily adjust as needed. It hard to guess how long it will take each step. This assumes each step takes same amount of time. This is how ProgressIndicator works.

ClearAll[n, m, p];
f[n_] := FactorInteger[2^n - 1];

nRows = 10;
nCols = 20;
total = nRows*nCols;
p = 0;

Grid[{
  {Row[{"row ", Dynamic@m, " column ", Dynamic@n}]},
  {ProgressIndicator[Dynamic[p], {1, total}]}
  }]

Do[
 Do[
  p += 1;
  f[p],
  {m, 1, nRows}
  ],
 {n, 1, nCols}
 ]

now

answered May 16 '18 at 18:30

Nasser

143,286
11
154
359

Thanks for both suggestions. I'm away from my computer iuntil morning now, but will report back. – Richard Burke-Ward May 16 '18 at 19:14
Both of these work. I can only tick the one that's proposed as an answer, though. Much appreciated. – Richard Burke-Ward May 17 '18 at 07:38

Progress bar / counter for multi-row table with 2 variables

1 Answers1