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Assuming that I only have access to the plot and not to the function that was used to generate it, how can I get the coordinates of the x-intercept of this plot?

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user3318424
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    Please make precise a few points. First, what do you mean by "having access to the plot". Do you have the plot in the form of an image? Say, a pdf file with the image? Or something else? Second, please make it more precise, what do you mean under "x-intercept"? Do you mean the value of x close to 6.3, where the plot ends up, or something else? – Alexei Boulbitch Feb 13 '19 at 13:59
  • I have the plot as an image only. The x-intercepts are all those points where their y-coordinate is equal to 0. I would like to get their x-coordinates. – user3318424 Feb 13 '19 at 14:20
  • In this case, there is a way, if you agree that the points of the plot you will obtain with a certain approximation. Some time ago I published a function entitled "copyCurve" that can help you. You find it here: https://mathematica.stackexchange.com/questions/44355/how-to-make-a-curve-selectable-from-a-scaned-image-and-convert-it-to-a-list-of-c/44358#44358 – Alexei Boulbitch Feb 13 '19 at 14:38

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