Using mesh for a single function inside Plot

Question

Plot[{Sin[x], Cos[x]}, {x, 0, 10}, Mesh -> {{0, π}}, MeshShading -> {Black, Red}]

In the above, how can I specify that I want the mesh for just, say the Sin function and not the Cos? I know I can use two plots and combine them with Show, but this is not what I want.

Show[ {Plot[Sin[x], {x, 0, 10}, Mesh -> {{0, \[Pi]}}, MeshShading -> {Black, Red}], Plot[Cos[x], {x, 0, 10}, Mesh -> {{0, \[Pi]}}]}] — Dr. belisarius, Feb 07 '13 at 16:59
@belisarius Isn't this what the OP explicitly says he doesn't want, or am I misreading this? — Sjoerd C. de Vries, Feb 07 '13 at 21:52
@SjoerdC.deVries Yup. But my preferred shoe shop doesn't sell pairs of two right shoes unless you can convince them -with good reasons- — Dr. belisarius, Feb 07 '13 at 21:59
Since your own answer has nothing to do with Mesh shall we assume that you just want output that visually matches the graphic shown in that answer? — Mr.Wizard, Mar 10 '13 at 19:09
Yes, that's true, I just wanted to get the visuals of the answer in a single plot command. — Andrei, Mar 17 '13 at 12:02

score 1 · Answer 1 · answered Feb 08 '13 at 14:28

1

Plot[{ConditionalExpression[Sin[x], 0 <= x <= Pi], 
      ConditionalExpression[Sin[x], Pi < x <= 10], Cos[x]}, {x, 0, 10}, 
      PlotStyle -> {Red, Black, Black}]

enter image description here

answered Feb 08 '13 at 14:28

Andrei

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3

This doesn't use Mesh at all, in contrast to what the question title states. – Jens Feb 09 '13 at 00:14
1

It is a good answer if the real question is how to generate that plot... – SEngstrom May 09 '13 at 15:32

score 0 · Answer 2 · answered Jan 02 '18 at 08:53

0

Plot[{Sin[x], Cos[x]}, {x, 0, 4 Pi}, 
 MeshFunctions -> {Boole[#2 === Sin[#1]] # &},
 Mesh -> {{0, Pi, 2 Pi, 3 Pi, 4 Pi}}, 
 MeshShading -> {Black, Directive[ Red, Thick]},
 PlotPoints -> 900]

answered Jan 02 '18 at 08:53

kglr

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Using mesh for a single function inside Plot

2 Answers2