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I would like to solve the following differential equation

$\frac{d^2 \psi(r_*)}{dr^2_*} + (\omega^2 - V(r)) \psi(r_*)=0$

and the boundary conditions are $\psi(\inf) = \psi(-inf) = 0$. The problem is that the function V(r) is defined in $r$, not $r_*$. However I have the following relation

$r_* = r+2M ln(r-2M)$

which, clearly, cannot be solved for $r$.

My real problem is to find the eigenvalues for $\omega$, but any help how to deal with this implicit definition of $r$ may help me.

PS: I am posting this here and not in physics/math exchange because the function $V(r)$ is complicated and I need to solve it computationally. And no, I do not want to transform the whole equation to the $r$ coordinate and solve it in there.

  • This is a duplicate, but there is no answer either. I investigated this operator, but I do not know yet what is required to receive. We can repeat someone's result. But the author did not give a link to the article. – Alex Trounev Jul 15 '19 at 15:26
  • Does f = r \[Function] r + 2 M Log[r - 2 M]; g = InverseFunction[f] help? – Henrik Schumacher Jul 15 '19 at 22:33

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