I want to plot the complex sequence of numbers $(1/(1 + I))^n$ so that I can roughly see divergence/convergence. I tried DiscretePlot but doesn't seem to work.
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1There are many ways to do this. One example is plotting-complex-numbers – Nasser Nov 29 '19 at 09:43
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4Write the complex sequence in polar form: $$1/\exp{( n * i * \pi / 4 )} / \sqrt{ 2 }^n ,,.$$ The sequence spirals around and approaches zero. – LouisB Nov 29 '19 at 10:12
2 Answers
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You can use the new in M12 function ComplexListPlot:
ComplexListPlot[Table[(1/(1+I))^n, {n, 10}]]
In earlier versions you can use ListPlot:
ListPlot[Table[ReIm[1/(1+I)^n], {n, 10}]]
If you want a continuous curve, you can use ParametricPlot:
ParametricPlot[ReIm[1/(1+I)^n], {n, 0, 10}]
Carl Woll
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I would be tempted to plot this in magnitude and phase:
c = Table[(1/(1 + I))^n, {n, 25}];
ListPlot[{Abs[c], Arg[c]}]
You can see the convergence of the magnitude to zero and the phase constantly decreasing with constant slope.
bill s
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