They're the same integral - the bottom integral is simply the top one split up using the identity $\log(xy) = \log(x) + \log(y)$. But the results aren't the same. Why?
Code for top integral:
NIntegrate[Exp[Log[Abs[(a - b) (a - c) (b - c) (a - 1) (b - 1) (c - 1)]] +
Log[Abs[a b c]] + 1/2 (-6 (a - b)^2 -
2 (a + b - 2 c)^2 - (a + b + c - 3)^2 - (a + b + c +
1)^2)] Boole[a <= b <= c <= 0], {a, -Infinity, 0}, {b, -Infinity, 0}, {c, -Infinity, 0}]
Code for bottom integral:
NIntegrate[ Exp[Log[Abs[a]] + Log[Abs[a - b]] + Log[Abs[b]] + Log[Abs[a - c]] +
Log[Abs[b - c]] + Log[Abs[c]] + Log[Abs[a - 1]] +
Log[Abs[b - 1]] + Log[Abs[c - 1]] + Log[Abs[1]] +
1/2 (-6 (a - b)^2 -
2 (a + b - 2 c)^2 - (a + b + c - 3 )^2 - (a + b + c +
1)^2)] Boole[a <= b <= c <= 0], {a, -Infinity, 0}, {b, -Infinity, 0}, {c, -Infinity, 0}]
The result seems so much like nonsense that I was sure there was a typo in the two expressions, but I checked that the two are equal using FullSimplify[top integrand - bottom integrand] (need to take out the Exp command for this to evaluate quickly, though). That leaves a numerical effect somewhere, and the fact that I need to not exponentiate both integrands to calculate the FullSimplify + the fact the bottom integral takes significantly longer to evaluate than the top one + the error message in the bottom integration certainly looks like a numerical effect, but I can't see what could possibly cause the numerical effect.

NIntegrate[ Exp[Log[Abs[a]] + Log[Abs[a - b]] + Log[Abs[b]] + Log[Abs[a - c]] + Log[Abs[b - c]] + Log[Abs[c]] + Log[Abs[a - 1]] + Log[Abs[b - 1]] + Log[Abs[c - 1]] + Log[Abs[1]] + 1/2 (-6 (a - b)^2 - 2 (a + b - 2 c)^2 - (a + b + c - 3)^2 - (a + b + c + 1)^2)] (*Boole[a\[LessEqual]b\[LessEqual]c\[LessEqual]0]*), \ {a, -Infinity, 0}, {b, -Infinity, a}, {c, -Infinity, b}], which is a more efficient formulation, too. – Michael E2 Feb 03 '20 at 20:54Boolehelps immensely:NIntegrate[ Exp[Log[Abs[a]] + Log[Abs[a - b]] + Log[Abs[b]] + Log[Abs[a - c]] + Log[Abs[b - c]] + Log[Abs[c]] + Log[Abs[a - 1]] + Log[Abs[b - 1]] + Log[Abs[c - 1]] + Log[Abs[1]] + 1/2 (-6 (a - b)^2 - 2 (a + b - 2 c)^2 - (a + b + c - 3)^2 - (a + b + c + 1)^2)] Boole[a <= b <= c <= 0], {a, -Infinity, 0}, {b, -Infinity, a, 0}, {c, -Infinity, b, 0}]– Michael E2 Feb 03 '20 at 20:55