1

i have this equation

y= (5.41*10^-15 E^(-148/T))/T^(3/2) + (
 2.00122*10^-10 E^(-((
   53.124 (1 + (59.357 T - 1.0404 T^2 + 0.0091653 T^3)/(
  1000 + 201.65 T + 2.7621 T^2 + 0.00098305 T^3))^(1/3))/T^(
   1/3))))/(
  T^(2/3) (1 + (59.357 T - 1.0404 T^2 + 0.0091653 T^3)/(
   1000 + 201.65 T + 2.7621 T^2 + 0.00098305 T^3))^(5/6))

I can plot it easily with the Plot command

 Plot[y, {T, 10, 1000}, Frame -> True, 
 PlotRange -> {{10, 1000}, {10^-20, 5 10^-16}}]

but i would like the x frame to be in logarithmic form, so i used LogLinearPlot

however, it shows the wrong plot and it does not apply on my desired range. 

  LogLinearPlot[y, {T, 10, 1000}, Frame -> True]

or

  LogLinearPlot[y, {T, 10, 1000}, Frame -> True, PlotRange -> 
  {10^-20, 10^-16}]

the correct figure is figure 2.

what is the problem?

enter image description here

user68857
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1 Answers1

2

your code is right.

LogLinearPlot[y, {T, 10, 1000}, Frame -> True, PlotRange -> {Automatic, {0, 4*^-16}}]

and

Plot[y, {T, 10, 1000}, Frame -> True, PlotRange -> {Automatic, {0, 4*^-16}}]

both give out the right graph.

you can notice that the peak of function is at the same position.

AsukaMinato
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  • thanks for your response. but the first command gives very small cure @wuyudi i edited the question with a picture – user68857 Feb 05 '20 at 11:04