I try this numerical summation (in two parts)
a = NSum[(HarmonicNumber[2 m])/m^3, {m, 1, Infinity},
WorkingPrecision -> 100, PrecisionGoal -> 100];
N[Pi^3/24 Log[2]^2 + Log[2] Pi/16 Zeta[3] - Pi^5/960 - Pi/16 a, 100]
and this numerical integration
NIntegrate[x^2 Log[Sin[x]] Log[Cos[x]], {x, 0, Pi/2},
WorkingPrecision -> 100, PrecisionGoal -> 100]
which are supposed to give the same result, and they do, but only to 25 places.
Obviously, at least one of the results is off. How can I increase the precision so that these agree past 25 places? If that can't be done, which of these is the more accurate?
If I try to evaluate the first quantity symbolically, I get
b = Sum[(HarmonicNumber[2 m])/m^3, {m, 1, Infinity}]
1/144 (π^4 + 72 (EulerGamma + Log[4]) Zeta[3] - 36 Sqrt[π] (HypergeometricPFQRegularized^({0, 0, 0, 0, 0}, {0, 0, 0, 1}, 0))[ {1, 1, 1,1, 3/2}, {2, 2, 2, 3/2}, 1])
However, N[b,20] never returns. The problem seems to be the evaluation of the derivative of HypergeometricPFQRegularized.
N[b, 70], but trying to evaluate it in8.0.4its just taken a few minutes and I still have got no result. I'll look later if one can do it successfully inver. 8. I think you could try some methods inSum` to work around this issue. – Artes Mar 16 '13 at 03:46HypergeometricPFQRegularizedby itself at the given point, and have left it running for over 30 minutes with no response. Thanks for the help. – robjohn Mar 16 '13 at 03:50ver.8not present inver.9, see comments above. I'll have to take a closer look if it can be explained to a larger extent and then I'll update my answer. – Artes Mar 16 '13 at 12:30