0

I'm looking to laser cut a bunch of hexagons and assemble them into a torus (using hot glue or tape). How do I get the dimensions of the individual unique hexagons? I've seen Create a torus with a hexagonal mesh for 3D-printing but it didn't help me. I'd like to use n=30, m=10 and keep the hexagons conformally parametrized if possible.

Michael Tomlin
  • 1
  • Welcome to Mathematica.SE! I suggest the following:
    1. As you receive help, try to give it too, by answering questions in your area of expertise.
    2. Take the [tour] and check the faqs!
    3. When you see good questions and answers, vote them up by clicking the gray triangles, because the credibility of the system is based on the reputation gained by users sharing their knowledge.

    Also, please remember to accept the answer, if any, that solves your problem, [by clicking the checkmark sign](http://tinyurl.com/4srwe26

     – Dunlop Mar 30 '20 at 20:30
  • Can you explain why the link didn't help you? There are several examples there where you can get a Graphics3D object containing polygons, these you would be able to extract and get the dimensions. – Dunlop Mar 30 '20 at 20:33
  • How do I get the dimensions? I've never used Mathematica before so I'm clueless – Michael Tomlin Mar 31 '20 at 15:37
  • I've tried using //InputForm and I got a long list of what look like coordinates but there's no way to know what order they are listed in
    *Graphics3D[GraphicsComplex[ {{1.3600677225069995, -0.06787815808490266, 0.1162781963383075}, {1.3829308389414996, 0., 0.}, {1.3760587449486854, 0.13769544562435124, 0.}, {1.3465507584441911, 0.20295987062409462, 0.1162781963383075}, {1.3196511679801861, 0.33602447678540626, 0.1162781963383075},     – Michael Tomlin Apr 01 '20 at 14:58

0 Answers0