How is this false?

Question

Why is the result of this False? Am I blind?

k *t^2/(2 * t) + k /(2 * t) === (k * t^2 + k)/(2 * t)

False

SameQ vs. Equal. Use == instead of ===. The triple === is used to test if they are the same expression. It does not test mathematical equivalence. Read the "Background & Context" of SameQ for more discussion. — Michael E2, Aug 29 '20 at 15:25
If you want True, then I'd suggest Simplify[difference] == 0. -- BTW, folks generally prefer code to be posted than images. It makes it easier for them to test their ideas on your example(s). — Michael E2, Aug 29 '20 at 15:30
@MichaelE2 == or Equal does not give a True/False output. It gives this uninformative output. I can put any rubbish in there and it would show it the same. — Mihail, Aug 29 '20 at 15:31
Simplify[k*t^2/(2 t) + k/(2 t) == (k*t^2 + k)/(2*t)] gives True. You need to put the expressions into the same form to compare them. — flinty, Aug 29 '20 at 16:39
I did have a suggestion. Did you see it? (Actually, two, but I mean the Simplify one.) — Michael E2, Aug 29 '20 at 17:33
Does this answer your question? Testing equivalence of analytical expressions like $x^2 -x == x(x-1)$ — Michael E2, Aug 29 '20 at 17:37

score 1 · Answer 1 · answered Aug 29 '20 at 17:21

1

Reduce[k*t^2/(2*t) + k/(2*t) == (k*t^2 + k)/(2*t)]

(* True *)

answered Aug 29 '20 at 17:21

David Keith

1 Answers1