3

When I try to find

θ = ArcCos[-.5]

I am expecting more than one answer: $$2 \pi/3, 4\pi/3,...$$

But Mathematica is returning only one: 2.0944 and it is not in angle format as well. Is there a way to get all the values of angles in angle format?

Conor
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Jasmine
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2 Answers2

5

you could define a new version of ArcCos[] to produce the desired behaviour

arcCos[θ_] := Solve[θ == Cos[x] , x]

enter image description here

Conor
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4

Try the equivalent

Solve[-1/2 == Cos[θ], θ]

and you get multiple values

Conor
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Andreas
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