Here is my attempt, based on the code you provided. I first replaced the formula you had for p directly in the set of equations, as it depended on T[z,t,r].
As pointed out by @Daniel Huber, you should use Integrate in A and B, with the assumption that $q>0$ for convergence.
Following the answer in this question, you should be able to solve your set of equations assuming q and v also depend on (z,t,r), not just on z.
Since you don't have any parameter, I use NDSolveValue instead of ParameterNDSolveValue. You will have some warning messages, but NDSolve will go through and give you some interpolating function, that you can visualise with SliceContourPlot3D.
Please, tell me if this can help you.
Cheers
ClearAll["Global`*"];
equ = With[{v = v @@ {z, t, r}, q = q @@ {z, t, r}, T = T @@ {z, t, r},
A = Integrate[r*Exp[-q[z, t, r]*r^2]/(1 + T[z, t, r]^(-3/2)), {r, 0, Infinity},
Assumptions -> q[z, t, r] > 0], B = Integrate[r*Exp[-2 q[z, t, r]*r^2]/(1 + T[z, t, r]^(-3/2)), {r, 0, Infinity}, Assumptions -> q[z, t, r] > 0]}, {-v D[q, z] +
q*D[v, z] == -q^2*v*A, -v*D[q, z] + 2 q*D[v, z] == -4*q^2*v*B,
D[T + (1/(1 + T^(-3/2)) + 1) v^2 Exp[-2 q r^2], t] +
1/r D[r*(1/(1 + T^(-3/2)))*v^2 Exp[-2 q r^2], r] +
D[(1/(1 + T^(-3/2)))*v^2 Exp[-2 q r^2], z] == (1/(1 + T^(-3/2)))*
v^2 Exp[-2 q r^2]}]
ic = {v[0, t, r] == 1, q[0, t, r] == 1, T[0, t, r] == 1}
{vsol, qsol, Tsol} = NDSolveValue[{equ, ic}, {v, q, T}, {z, 0, 10}, {t, 0, 10}, {r, 0.1,10}]
SliceContourPlot3D[vsol[z, t, r], "ZStackedPlanes", {z, 0, 10}, {t, 0, 10}, {r, 0.1,10}]
NIntegratecan not integrateNIntegrate[p*Exp[-q*r^2] r, {r, 0, \[Infinity]}]with undefinedq. Same thing forB– Daniel Huber Apr 20 '21 at 09:48qshould be solve numerically? Thus, is it the problem ofNIntegratein mma? No way around in mma? – sixpenny Apr 20 '21 at 10:21NIntegratecan only integrate numerical functions. Non numerical functions may be integrated usingIntegrate– Daniel Huber Apr 20 '21 at 10:47T[0,0,0]==1meansT[z,0,r]==1? – Alex Trounev Apr 20 '21 at 17:20