Mathematica 9 can't integrate this function but earlier versions could

Question

Integrate[ ArcTan[x]/(1 + x) Log[(1 + x^2)/2], {x, -1, 1}]

I used Mathematica 9.0.1 on Windows7 32bit, Mathematica 9 cannot compute this, but Mathematica 8 gives Pi^3/96, is this a bug?

I get the same result with Mathematica 9, but, admittedly, it took 3 times as long as with v8... — sebhofer, Jun 13 '13 at 08:32
I have to correct myself, I now (after quitting the kernel) get Infinity (as pointed out by Artes)... No clue what went wrong before. — sebhofer, Jun 13 '13 at 16:21
@explorer Couldn't Mathematica 9 really return any result or colud it return Infinity as I demonstrated in my answer? Have you tried to integrate TrigToExp@ArcTan[x] ? — Artes, Jun 16 '13 at 17:19
This is fixed in around 13.2.1. Both this and Integrate[( 1/2 I Log[1 - I x] - 1/2 I Log[1 + I x])/(1 + x) Log[(1 + x^2)/ 2], {x, -1, 1}] — Валерий Заподовников, Jun 28 '23 at 16:59

score 9 · Accepted Answer · answered Jun 13 '13 at 08:43

This issue reminds many similar problems with Integrate. We have in Mathematica 8.0.4:

Integrate[ ArcTan[x]/(1 + x) Log[(1 + x^2)/2], {x, -1, 1}]

Pi^3/96

However in Mathematica 9.0.1 it takes quite a long time yielding a different result:

Integrate[ ArcTan[x]/(1 + x) Log[(1 + x^2)/2], {x, -1, 1}]

Infinity

This is a bug, we can compare it with the NIntegrate result which yields the number numerically the same as in ver. 8.

Of course the result should be the same if we substitute ArcTan by its equivalent:

TrigToExp[ ArcTan[x] ]

1/2 I Log[1 - I x] - 1/2 I Log[1 + I x]

but now the result is the same as in ver. 8:

Integrate[ TrigToExp[ ArcTan[x]]/(1 + x) Log[(1 + x^2)/2], {x, -1, 1}]

Pi^3/96

This is now fixed at least in 13.2.1. – Валерий Заподовников Jun 28 '23 at 17:00 — Валерий Заподовников, Jun 28 '23 at 17:00

1 Answers1