I am using Series function on (1/z)(-k^2)^z. Up to z^0, the function gives me 1/z + Log[-k^2]. But in the standard textbook on QFT, it turns out the expansion should give 1/z + Log[k^2/mu^2] -i*pi up to z^0 in the series. Could you explain the reason behind such discrepancy? How to resolve it?
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2Is there a chance you could show the Mathematica code you typed? This will make it easier to try it – Nasser Sep 27 '23 at 06:15
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...and tell the reader what QFT stands for...? – David G. Stork Sep 27 '23 at 06:15
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Quantum Field Theory! – NovoGrav Sep 27 '23 at 06:29
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f[z_]:=(1/z)(-k^2)^z; Series[f[z],{z,0,1}] – NovoGrav Sep 27 '23 at 06:30
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There is probably a constant $\mu$ present in your Quantum Field Theory book.
For the rest, analytically, your function has definition
$$\frac{1}{z}\left( -k^2\right)^z= e^{z \log(-k^2) - \log z} = e^{2 z \log k\ \pm i \ \pi \ z - \log z}$$
Roland F
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