2
FindSequenceFunction[{1, 2, 5, 14, 41}, n]

1/6 (3 + 3^n)

You can directly calculate the general term formula above

Why is it impossible to find the general term formula below?

In[1]:= FindSequenceFunction[{2^1, 2^2, 2^5, 2^14, 2^41}, n]

Out[1]= FindSequenceFunction[{2, 4, 32, 16384, 2199023255552}, n]

The result should be:

2^(1/6 (3 + 3^n))
csn899
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1 Answers1

5

A workaround:

seq = Log@{2^1, 2^2, 2^5, 2^14, 2^41}

FindSequenceFunction[seq, n] // FullSimplify // Exp

2^(1/6 (3 + 3^n))

Syed
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