How to define a variable as a function of another variable?

Question

I want to define a variable q which is a function of t. And I want to define another variable qdot = dq/dt.

Then what I want to archive is that if I have a function f = a*Sin[q], and when I take the derivative df = D[f,t], Mathematica returns:

a*qdot*Cos[q].

Is there a way to do this?

You mean like this: f[t_] := a*Sin[q[t]]; D[f[t], t] gives a Cos[q[t]] q'[t] — Nasser, Aug 20 '13 at 19:13
@belisarius The problem with Dt[] is that the constant in my function also got differentiated. — auzn, Aug 22 '13 at 04:14
@Nasser I tried your suggestion and it gives me a good result. I can even define q'[t_]:=qdot[t], so D[f[t],t] gives Cos[q[t]]qdot[t] — auzn, Aug 22 '13 at 14:17
@Nasser If this works for the OP, please consider posting an answer:) — Kuba, Sep 23 '13 at 23:51
@Kuba oh, this was long time ago. I do not think the answer is worth posting as it nothing new. It is just a derivative. May be OP can close this question if they wish ;) — Nasser, Apr 26 '14 at 11:10
@Nasser I don't think OP is around. And I already voted here so I can't again :/ — Kuba, Apr 26 '14 at 11:12
@belisarius Added a bit about the Constant attribute to your solution. — Ian, Jun 05 '15 at 22:31

score 8 · Accepted Answer · answered Jun 05 '15 at 22:30

8

The total derivative Dt will give you an answer assuming every symbol has a derivative, unlike the partial derivative D. To protect your constant, you can give it the attribute Constant.

SetAttributes[a, Constant]
f = a Sin[q];
Dt[f, t]
(* a Cos[q] Dt[q, t] *)

answered Jun 05 '15 at 22:30

Ian

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Nice experiment – Dr. belisarius Jun 06 '15 at 01:12
Yes, definitely a worthwhile effort. I shall endeavor to do the same, my good sir! (+1) – MarcoB Jun 09 '15 at 21:22

How to define a variable as a function of another variable?

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