1

I have an integration with assumptions and limits of integration. I tried to use Mathematica to solve this problem, but I cannot get any results.

Integrate[1/(w^4 + 2 (2 ξ^2 - 1) w^2 ω1^2 + ω1^4), {ω1, 0, t}, 
  Assumptions -> {w > 0, 1 > ξ > 0}]]

What should I do?

m_goldberg
  • 107,779
  • 16
  • 103
  • 257
whdwpy666
  • 11
  • 2

1 Answers1

2

Evaluating the indefinite integral works better.

sol = Integrate[1/(w^4 + 2 (2 v^2 - 1) w^2 w1^2 + w1^4), w1, Assumptions -> {w > 0, 1 > v > 0}]

(* (-(ArcTan[w1/(Sqrt[-1 + 2*v^2 + 2*v*Sqrt[-1 + v^2]]*w)]/
   Sqrt[-1 + 2*v^2 + 2*v*Sqrt[-1 + v^2]]) - 
   ArcTanh[w1/(Sqrt[1 - 2*v^2 + 2*v*Sqrt[-1 + v^2]]*w)]/
   Sqrt[1 - 2*v^2 + 2*v*Sqrt[-1 + v^2]])/(4*v*Sqrt[-1 + v^2]*w^3) *)

If the limits of integration are important, then evaluate

sol/.w1 -> t - sol/.w1 -> 0

(The second term, incidently, is 0.)

bbgodfrey
  • 61,439
  • 17
  • 89
  • 156
  • @Nasser I don't see anything wrong with this answer. Just different letters. – Jens Mar 07 '15 at 04:53
  • @Jens oh sorry, I saw 2 w's in there. did not notice one had 1 stuck to it. – Nasser Mar 07 '15 at 05:10
  • Actually I want the final limits, w1->infinity-w1->0, and the assumption 1>v>0.@bbgodfrey – whdwpy666 Mar 09 '15 at 01:46
  • @whdwpy666 The limits you request were not part of your Question but can applied easily to obtain, (Pi*(Sqrt[-(1/((1 - 2*v^2 + 2*v*Sqrt[-1 + v^2])*w^2))] - Sqrt[1/((-1 + 2*v^2 + 2*v*Sqrt[-1 + v^2])*w^2)]))/(8*v*Sqrt[-1 + v^2]*w^2) The assumption 1>v>0 was used to obtain the answer, as requested. – bbgodfrey Mar 09 '15 at 02:16