1

How can I get the output expressed in terms of p1 and p2 instead of exponentials?

gau[x_, v_] := Exp[-(x^2)/(2*v)]/Sqrt[2*Pi*v];
p1[x_] := gau[x - m, B + v]/2 + gau[x + m, B + v]/2;
p2[x_] := gau[x - m, B + v]/2 - gau[x + m, B + v]/2;
Simplify[D[Log[p1[x]], {v, 3}]]

I want to substitute:

Exp[(x+m)^2/(2*(B+v))]/2 + Exp[(x-m)^2/(2*(B+v))]/2 -> p1
Exp[(x+m)^2/(2*(B+v))]/2 - Exp[(x-m)^2/(2*(B+v))]/2 -> p2

but obvious that doesn't work.

Dr. belisarius
  • 115,881
  • 13
  • 203
  • 453
Jerry Guern
  • 4,602
  • 18
  • 47

0 Answers0