Expand the plotting range

Question

When use the following command to plot a graph

Plot[x^(1/3), {x, -1, 1}]

Mathematica does not show the range [0, 1]. It does not show the range [-1, 0]. While for function 1/x it does.

Plot[1/x, {x, -1, 1}]

How can I make Mathematica show the range specified for x^(1/3) ?

It doesn't plot imaginary numbers (such as the root of a negative number) because the plot coordinate system is over the real cartesian 2D space. You can use Re to obtain the real component and plot that. — C. E., Jul 04 '15 at 21:30
There's also CubeRoot and Surd for real-valued functions. — Michael E2, Jul 04 '15 at 22:19
The problem is not with Plot but with the cube root itself. See Finding real roots of negative numbers. — , Jul 04 '15 at 22:51
I'm voting to close this question as off-topic because the issue it raises is not a Mathematica issue but a mathematics one. — m_goldberg, Jul 04 '15 at 23:09

Enrique Pérez Herrero · Answer 1 · 2015-07-04T21:43:55.053

2

Plot[{Re[x^(1/3)], Im[x^(1/3)]}, {x, -1, 1}]

or plotting the modulus:

Plot[Abs[x^(1/3)], {x, -1, 1}]

edited Jul 04 '15 at 21:43

answered Jul 04 '15 at 21:29

1

With PlotRange->Full, Mathematica still only show the positive range. (I use Mathematica 9.) – Ben Wu Jul 04 '15 at 21:40

1 Answers1