If I try:
RegionPlot[{y > x - 1 && y^2 < 2 x + 6}, {x, -4, 6}, {y, -3, 5},
Mesh -> None]
I get:
However, if I combine it with a ContourPlot:
Show[
ContourPlot[{y == x - 1, y^2 == 2 x + 6}, {x, -4, 6}, {y, -3, 5},
Axes -> True, AxesLabel -> Automatic,
PlotLegends -> "Expressions"],
RegionPlot[{y > x - 1 && y^2 < 2 x + 6}, {x, -4, 6}, {y, -3, 5},
Mesh -> None]
]
I get this:
Is there any way to get rid of all the mesh-like segments in the image? I did try Mesh->None.
Guess who it is idea worked:
Show[
ContourPlot[{y == x - 1, y^2 == 2 x + 6}, {x, -4, 6}, {y, -3, 5},
Axes -> True, AxesLabel -> Automatic,
PlotLegends -> "Expressions"],
RegionPlot[{y > x - 1 && y^2 < 2 x + 6}, {x, -4, 6}, {y, -3, 5}],
Method -> {"TransparentPolygonMesh" -> True}
]
Produced:



Method -> {"TransparentPolygonMesh" -> True}inShow[]. – J. M.'s missing motivation Aug 13 '15 at 22:52