Why variable in SparseArray can't be replaced?

Asked Oct 28 '15 at 16:38

Active Oct 28 '15 at 16:38

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SparseArray[{1, 1} -> t] /. t -> 1

Still contains t. Why t is not replaced by 1?

asked Oct 28 '15 at 16:38

matheorem

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Atomic objects don't really work like that. Anyway: use ArrayRules[] to convert to a list of nonzero entries and their corresponding positions, make your replacements, and then convert back to SparseArray[]. – J. M.'s missing motivation Oct 28 '15 at 16:48
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This question might be a duplicate of this: http://mathematica.stackexchange.com/questions/13790/using-replaceall-on-sparsearray – Arnoud Buzing Oct 28 '15 at 16:51

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