Radial range in polar plot

Question

I'm trying to make a polar plot. The radial range (radius of the circle) is automatically set at 1.2. I want to change this to 1. My code is:

PolarPlot[Abs[1/2 (E^(I t) + 1)]^2, {t, 0, 2 π}, 
 PlotStyle -> {Darker[Blue], Thick},
 PolarAxes -> True,
 BaseStyle -> {FontFamily -> "Arial", FontSize -> 12},
 PolarTicks -> {{0, Pi/4, Pi/2, (3 Pi)/4, Pi, (5 Pi)/4, (3 Pi)/2, 
  (7 Pi)/4}, {0, .2, .4, .6, .8, 1}},
 PolarGridLines -> {{0, Pi/2, Pi, 3 Pi/2}, {0.25, 0.5, 0.75, 1}}]

On the internet I found the command PlotRange -> 1, but this makes it even worse.

PolarPlot[Abs[1/2 (E^(I t) + 1)]^2, {t, 0, 2 π}, 
 PlotStyle -> {Darker[Blue], Thick},
 PlotRange -> 1,
 PolarAxes -> True,
 BaseStyle -> {FontFamily -> "Arial", FontSize -> 12},
 PolarTicks -> {{0, Pi/4, Pi/2, (3 Pi)/4, Pi, (5 Pi)/4, (3 Pi)/2, 
  (7 Pi)/4}, {0, .2, .4, .6, .8, 1}},
 PolarGridLines -> {{0, Pi/2, Pi, 3 Pi/2}, {0.25, 0.5, 0.75, 1}}]

Does anyone know how to do this? Thanks in advance!

Possible duplicate of ListPolarPlot not showing full plot range even with PlotRange -> All — shrx, Oct 30 '15 at 13:58
Greetings Linde! To make the most of Mma.SE please take the [tour] now. Help us to help you, write an excellent question. Edit if improvable, show due diligence, give brief context, include minimum working examples of code and data in formatted form. As you receive give back, vote and answer questions, keep the site useful, be kind, correct mistakes and share what you have learned. — rhermans, Oct 30 '15 at 14:08
This is definitely *not* a duplicate of the question shrx picks it to be a duplicate of and there is no answer for this question there. — m_goldberg, Oct 30 '15 at 20:21

score 10 · Answer 1 · edited Nov 16 '16 at 16:43

Use PolarAxesOrigin like this: PolarAxesOrigin -> {0, 1}

PolarPlot[
 Abs[1/2 (E^(I t) + 1)]^2, {t, 0, 2 π}
 , PlotStyle -> {Darker[Blue], Thick}
 , PlotRange -> 1.2
 , PolarAxesOrigin -> {0, 1}
 , PolarAxes -> True
 , BaseStyle -> {FontFamily -> "Arial", FontSize -> 12}
 , PolarTicks -> {{0, Pi/4, Pi/2, (3 Pi)/4, 
    Pi, (5 Pi)/4, (3 Pi)/2, (7 Pi)/4}, {0, .2, .4, .6, .8, 1}}
 , PolarGridLines -> {{0, Pi/2, Pi, 3 Pi/2}, {0.25, 0.5, 0.75, 1}}
 ]

Or for a better fit

PolarPlot[
 Abs[1/2 (E^(I t) + 1)]^2, {t, 0, 2 π}
 , PlotStyle -> {Darker[Blue], Thick}
 , PlotRange -> 1.2
 , PolarAxesOrigin -> {0, 1}
 , PolarAxes -> True
 , BaseStyle -> {FontFamily -> "Arial", FontSize -> 12}
 , PolarTicks -> {{0, Pi/4, Pi/2, (3 Pi)/4, 
    Pi, (5 Pi)/4, (3 Pi)/2, (7 Pi)/4}, {0, .2, .4, .6, .8, 1}}
 , PolarGridLines -> {{0, Pi/2, Pi, 3 Pi/2}, {0.25, 0.5, 0.75, 1}}
 ]

Thanks! That's just what I needed :) – Linde Oct 30 '15 at 14:05 — Linde, Oct 30 '15 at 14:05

Radial range in polar plot

1 Answers1