Run command didn't work

Question

I am trying to use external ffmpeg.exe to convert list of image files into mp4

a = Table[Plot[Sin[ω t], {t, 0, 10}, PlotRange -> {-1, 1}, ImageMargins -> .4], 
         {ω, .1, 2, .1}];

Export["movie01.png", a, "VideoFrames"];
Run["ffmpeg -f image2 -framerate 12 -i movie%02d.png -c:v libx264  movie.mp4"]

But the conversion is not done. If I run the exactly same ffmpeg code in windows CMD, it works. What is wrong with the above Run command?

solution

It turns out that after adding new exe to the windows environment(in this case, ffmpeg.exe), we have to restart mathematica, or this new exe will not be recognized by mathematica.

Answer 1

Let's override the Run so it stops acting up.

Needs["NETLink`"];
InstallNET[];
Unprotect[Run];
Run[x___] := Module[{t, p},
   LoadNETType["System.IO.Directory"];
   Directory`SetCurrentDirectory[Directory[]];
   t = NETNew["System.Diagnostics.Process"];
   t@StartInfo@FileName = "C:\\Windows\\System32\\cmd.exe";
   t@StartInfo@Arguments = "/c " <> StringJoin@Riffle[{x}, " "];
   t@Start[];
   t@WaitForExit[];
   t@ExitCode];
Protect[Run];
Run["ffmpeg -f image2 -framerate 12 -i movie%02d.png -c:v libx264 movie.mp4"]

Someone is welcome to convert this to .NET link but as it stands the following works for me. This is the old code.

using System;
using System.Diagnostics;

public class Run{
 public static void Main(String[] arg) {
    string command = @"C:\Windows\System32\cmd.exe";
    Process process = new Process(); 
    process.StartInfo.FileName = command; 
    process.StartInfo.Arguments = "/c " + string.Join(" ",arg);
    process.Start(); 
  }
}

Compile it like so.

C:\Windows\Microsoft.NET\Framework\v4.0.30319\csc.exe Run.cs

and run it like so in Mathematica

Run["Run.exe ffmpeg -f image2 -framerate 12 -i movie%02d.png -c:v libx264  movie.mp4"]