Does every convex polyhedron have a combinatorially isomorphic counterpart whose angles between edges are rational multiples of $\pi$?

Asked Nov 18 '13 at 21:29

Active Oct 11 '17 at 22:38

Viewed 477 times

After reading these very interesting questions, I came up with another one:

Does every convex polyhedron have a combinatorially isomorphic counterpart whose angles between all pairs of edges meeting at a common vertex are rational multiples of $\pi$?

edited Apr 13 '17 at 12:58

Community

asked Nov 18 '13 at 21:29

Piotr Shatalin

2

In view of Mnev' universality theorem, there are rigid convex polytopes (in sufficiently high dimension) which do not have angles equal to rational multiples of $\pi$. – Misha Nov 19 '13 at 08:12

0 Answers0