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If $G$ is a Hausdorff topological group and $bG$ is its Bohr compactification, Wikipedia says that $G$ is called maximally almost periodic (MAP) if and only if the natural map $i : G \to bG$ is injective. Equivalently, MAP groups are those groups the points of which are separated by the finite-dimensional unitary representations. My question is:

if $G$ is MAP, is $i$ a homeomorphism onto $i(G)$, or is it only injective?

(I would like to know if topological properties and regular measures on $i(G)$ can be pulled back on $G$.)

Alex M.
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  • @FrancoisZiegler: Indeed, your answer there also answers my question, but before closing it myself let me also add you: does $i$ at least take Borel subsets to Borel subsets? I could have this if I imposed that $G$ and $bG$ were standard Borel spaces, but I was hoping that the topological group structure and compactness of $bG$ could make this assumption redundant. – Alex M. Mar 07 '18 at 12:37

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