What is the intuitive meaning behind Coulomb's constant $k_e$? If the force of an electric field can be calculated by
$$F=k_eqQ/d^2$$
If I could guess I would say $k_e$ is the acceleration but I am not sure.
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1Does it is a constant of proportionality suffice? Because that's really all it is. – Kyle Kanos May 13 '15 at 16:21
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Its the force experience by two unit charges by each other when separated by a distance of 1 metre.
user81128
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That is correct but OP is looking for an intuitive meaning of it. On the other hand I think your answer is as intuitive as it gets – Gonenc May 13 '15 at 14:32
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Coulomb's constant has units of metres per Farad. It is not acceleration; it is oftern expressed in terms of the vacuum permitivity for a free vacuum $k_\text{e} = \frac{1}{4\pi\varepsilon_0}$.
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