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A while ago someone proposed the following thought experiment to me:

A horse attached to a cart is resting on a horizontal road. If the horse attempts to move by pulling the cart, according to the 3rd Newton's Law, the cart will exert a force equal in magnitude and opposite in direction, cancelling each other out and thus the horse and the cart should not move. And yet it moves (pun intended ;) Why?

I never got a satisfactory answer, my guess is that the answer lies in the frames of reference involved: horse-cart and horse-road. Any ideas?

teto
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The opposing force always work on a different body, thats why they dont cancel. For instance the moon pulls the earth and the earth pulls the moon with same force. Also, the horse dont move by pulling the cart, but by pulling the earth.

TROLLHUNTER
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    you mean by "pushing the earth"? –  Dec 20 '10 at 18:55
  • I mean by alternately pulling and pushing the earth – TROLLHUNTER Dec 20 '10 at 19:27
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    Ambiguous answer , take Newtonian gravity fir example, two bodies exert equal gravitational forces on each other which would mean neither body should move as they both cancel out each other – user1062760 Aug 26 '16 at 01:10
  • Gravity doesn't mean neither body should move. If you start off with two still objects gravity will pull them together. They have equal and opposite forces, so the one on the right moves to the left, and the one on the left moves to the right. – bdsl Jan 27 '23 at 21:16
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The horse also exerts a force on the road, and the road reacts on the horse. To compute the movement of the horse, you need to add the 2 forces acting on the horse (by the road and by the cart).

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Let us draw free body diagram for the cart. It is important to note that reaction force is NOT acting on the cart. And that is why my friend it moves.

This does not mean that reaction is absent. It is there but its NOT acting on the cart itself. So not all the forces on the cart are balanced. There is net force.

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This is common misunderstanding. See examples here.