If the earth is rotating (e.g. at 1000km per hour, at the equator), how can planes safely land on a moving runway?
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11In the same way you safely land when you jump. – AccidentalFourierTransform Mar 31 '16 at 07:49
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It's 1667 km/h actually. – cst1992 Mar 31 '16 at 10:14
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Related: http://physics.stackexchange.com/q/1193/2451 and links therein. – Qmechanic Mar 31 '16 at 10:29
3 Answers
It is the relative velocity between the plane and the Earth which is important.
When the plane is at rest on the runway it is moving at 0 km/hr relative to the ground but also it is moving at 1000 km/hr due to the rotation of the Earth.
So if the plane is coming it to land at 150 km/hr that is 150 km/hr relative to the ground.
If a plane needs to travel due North then it does have to compensate for the rotation of the Earth and so must fly on a heading which is West of due North to arrive at a location where the speed of the Earth's rotation is less than 1000 km/hr.
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1While you are correct, but the rotating air plays an important role in maintaining that relative velocity. – Max Payne Mar 31 '16 at 08:54
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1While a plane may have to compensate for strong atmospheric winds indirectly caused by the rotation of the planet, if there were no wind and a plane traveled north from Africa, it would not have to compensate in order to not land in North America. – Neil Mar 31 '16 at 09:35
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@Neil Assume no atmosphere. On the Equator the plane and the Earth have a velocity of 1000 km/hr due East. As the plane travels North the Earth underneath it rotates at less than 1000 km/hr due East. – Farcher Mar 31 '16 at 13:43
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@Farcher Yes, but so does the plane. Everything rotates, not just the planet. You maintain the same rotation velocity as the planet when you take off. Why should the plane compensate? – Neil Mar 31 '16 at 14:26
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@Farcher You think that if the planet didn't have an atmosphere and you jumped at the equator, you'd land several hundred meters away? – Neil Mar 31 '16 at 14:35
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@Neil Where is the force that decreases the easterly speed of the plane as it moves further North so that the plane had the same lower rotational speed of the Earth? With no atmosphere if you dropped an object from a tower it would reach the ground a small distance East of the tower due to this effect. – Farcher Mar 31 '16 at 16:22
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@Farcher If you were in space moving at 1000km/hour and you let go of a bowling ball, would that ball move away from you in the opposite direction that you're moving? Absolutely not (at least not without a purposeful push). Add gravity to the equation and it's just the same problem with an irrelevant force vector. There's no invisible "friction" force being applied if it isn't attached to the rotating earth. If planes compensate for anything, it's headwind. – Neil Apr 01 '16 at 06:54
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Perhaps what I am trying to explain might be clearer. if the plane started at the North Pole and set off due South. The plane having started at the North Pole will not have a component of velocity at right angles to its motion due South. If you look out of the window of the plane what do you "see".? You see the Earth rotating in a direction at right angles to the motion of the plane. When the plane reaches the Equator it will arrive at a point which is West of the point which was originally due South of the plane when at the North Pole. – Farcher Apr 01 '16 at 07:27
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@Farcher Ah ok, I see what you meant. Yes, that does make sense, actually. – Neil Apr 04 '16 at 08:47
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@Neil I did not want to mention the fact before that this acceleration in a rotating frame (the Earth) is related to the Coriolis force. https://en.m.wikipedia.org/wiki/Coriolis_force – Farcher Apr 04 '16 at 09:25
The air, and the planes in the air, are rotating together with the Earth.
Everything is rotating!
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I'm not sur eI understand how the air rotates with the earth? How is it connected to it? If I throw a ball through the air, it moves through the air and independently of it – tmccar Mar 31 '16 at 10:43
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Imagine that you're running with a ball in your hand and while running you throw it in the air and then catch again. In those few seconds, while out of your hands, it continues to move alongside you, right? Even though it's not connected to you. It has velocity, so it keeps moving. So it is with air. It has velocity, so it keeps moving. Why does it have (roughly) the same velocity as things on the ground and earth itself? Friction with things on earth (like your face or a mountain) causes low air to get to the same speed, and friction with low air speeds up higher air if necessary, and so on. – AnatolyVorobey Mar 31 '16 at 11:04
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@tmccar think of it this way, if the air didn't move with the ground beneath it, standing at the equator you would experience winds 1667 km/h as you pass through the 'still' air. The air is moving relative to the ground. – James T Mar 31 '16 at 12:01
The fact that the Earth is rotating means that it is rotating around its own axis relatively to the surrounding space. The Earth's atmosphere – even though not opaque like the rocky planet's surface itself – is just the outmost layer of the planet. It is not a nonchalant part of the outer space. When the Earth orbits the Sun, it does not shed the atmosphere into the empty space all along the orbit, because the atmospheric layer belongs to the Earth. Take Jupiter, a gas planet: There wouldn't really be any tangible surface to land onto. Basically all you can see from outside is gas, yet all of that moves along with the planet, as one unit.
A hypothetical but impossible example: If only the Earth rotated at 1667 km/h but the surrounding atmosphere* didn't, the velocity is a relative one: While standing on the Earth's surface, you should basically be standing amidst a raging storm wind of 1667km/h, which isn't happening. Do not mix this hypothetical example with the weather system, which is an entirely different concept happening for other reasons.
*(which isn't a void vacuum, but a composition of gasses, therefore, matter which can interact with other matter. Colliding into gas molecules slowly doesn't feel like anything, but the bigger the velocity of collision, the more dramatic violence you can have mundane seeming particles cause: Still air can turn into house-tearing hurricanes when moving fast enough relatively to the houses.)
If you're traveling in a train and you jump, you land back where you were just like you hadn't even been in a moving train, because the air inside the train is traveling with it. If the train has no walls, it isn't carrying a portion of still air, but is slashing relatively very fast through the surrounding air. If you jump up now, the passing air will hit you hard and you'll fly far backwards relative to the train's floor. The Earth with its atmosphere is like the closed train that has walls.
Landing onto a rotating Earth seriously is a concern when astronauts return from space, because space is an airless zone and when you enter the Earth's atmosphere, the rotation of the planet suddenly starts to affect you. Similarly, when you launch a rocket to space, you can't just point it wherever you like, but you have to consider the Earth's rotating and orbiting factors. A bit like being in a moving train, opening the window and trying to throw a ball into a bucket that's sitting still next to the railway track.
But the train travels with a linear motion. So, as regarding the earth's rotational motion - if the train was shaped like a sphere (for example), and its motion was to rotate around its own centre (axis), would passengers not sense some sort of centrifugal force? – tmccar
Newton's laws of motion state that "When viewed in an inertial reference frame, an object either remains at rest of continues to move at a constant velocity, unless acted upon by a force". When you're in a fast carousel, you feel like you're being pushed outwards from its center. This feeling of pressure happens because according to classical mechanics, once set to motion into one direction, you'd really want to continue going that way in a straight line, but the supporting physical obstacles – the carousel's structure itself – blocks you from following that natural path, reflecting you back towards the carousel's center. You're getting a fight of two forces.
When you roll a ball at a straight wall in a diagonal angle, it will reflect back away in the identical but mirrored angle. You can observe that one reflection. Inside a circle, you'd want to just go straight out but your trajectory is being reflected back inwards at an extremely subtle angle at a time, and because the obstacle is curved, the moving object barely gets to travel on its newly reflected path at all when it already hits the circle wall again and is reflected time and time again, resulting to travel in what appears to be a circular path.
If you had a rotating sphere full of air, the air molecules near the edges would be more likely to occasionally collide with the wall, so there could be some turbulence there, but the air in the middle of the sphere would remain more untouched. If you were to have two spheres nested so that there's an outer shell sphere, and an inner smaller sphere which contains air – if the outer sphere rotates around its axis but the inner one that is in contact with the air inside doesn't, the inside remains fully intact and ambivalent of what's happening outside. If the space between the two sphere shells is a vacuum, there is no matter that could transfer the outer sphere's kinetic energy to the inner sphere. When a normal shaped train with air inside is in motion, the inside walls themselves are not moving relative to the air inside, so no air bouncing occurs. However, if you're standing on a train platform where the air is standing still and suddenly a train passes by, its walls hit the air molecules, causing a blast of wind.
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But the train travels with a linear motion. So, as regarding the earth's rotational motion - if the train was shaped like a sphere (for example), and its motion was to rotate around its own centre (axis), would passengers not sense some sort of centrifugal force? – tmccar Mar 31 '16 at 12:17
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@tmccar I updated my answer to address your new follow-up question. Comments don't allow that many characters. – user158589 Mar 31 '16 at 14:01