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Assume you've come in contact with a tribe of people cut off from the rest of the world, or you've gone back in time several thousand years, or (more likely) you've got a numbskull cousin.

How would you prove that the Earth is, in fact, round?

Qmechanic
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    That depends on the definition of "round". – Leos Ondra Sep 17 '13 at 06:38
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    At least two thousand years see http://en.wikipedia.org/wiki/Spherical_Earth#History – Selene Routley Nov 19 '13 at 12:31
  • This question appears to be off-topic because it is most appropriate on http://earthscience.stackexchange.com – BMS Dec 24 '14 at 22:59
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    Numbskull of a cousin? or a Flat Earther? If you're arguing with the latter, then he probably does not believe that the Earth is flat. He probably wants to demonstrate his own cleverness by confounding you with fallacies that you don't know how to disprove. – Solomon Slow Feb 28 '17 at 21:34
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    If I were forced to debate a Flat Earther, I would ask about the alleged conspiracy. If the Earth really is flat, then everything you've been told about how ships and airplanes navigate long trips is a lie, and every ship's officer and aircraft pilot is in on it. Ditto for some huge number of people working with space technology, and ditto for all of the astronomers. They've been keeping us in the dark for centuries. How have so many people kept so big a secret for so much time? What motivates them? – Solomon Slow Feb 28 '17 at 21:55
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    Would you have to stay in a room and convince the person through explanation or could you take them outside? If you aim a laser from the shoreline of a lake at a boat you can measure how high above the water you see the laser dot on the boat and do a very rough estimate of the curvature. Or, take them on a plane trip around the world that ends up in the same place. – Jack R. Woods May 23 '17 at 14:35
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    I'd just show them the space station live stream on youtube. Or attach their phone while on to a weather balloon. Or ask Felix Baumgartner. Or watch the vid of his WR flight https://www.youtube.com/watch?v=FHtvDA0W34I . So many ways. If they insist it is all fake, make them actually get crazy by showing them the brain in a vat wiki page and go do something actually productive for yourself: https://en.wikipedia.org/wiki/Brain_in_a_vat . Let them bury themselves into the notion you are only their imagination as well. – Vendetta May 31 '17 at 17:35
  • One other interesting point that puts a bit of turbulence to Flat Earth, though nothing so far as conclusive proof... is that the moon would have to rotate on its circular axis at exactly the rate it rotates around the Earth to maintain the same orientation of face as it rotates around Earth. Of course it does rotate on its axis already at the same rate as its orbital period, so I guess people could extend it to explain it away if they want to... but that leads to other complications. Just another oddity to endure to believe in a flat earth. – JeopardyTempest Sep 26 '18 at 00:55
  • Actually, that might be complexing to them than I thought about. Because you see the moon for about 1/2 it's time around the Earth... so shouldn't its face either turn 180° for you in relation to the North Pole during its transit through the sky... or be 180° off for someone opposite you (180° opposite longitude, at the same latitude) (and so the opposite end points to the North Pole?) There's other similar big issues... like how the days can be much longer to the south of the Equator in winter... when the sun would have to move at a faster circular rate for a day to still be 24 hr – JeopardyTempest Sep 26 '18 at 02:25
  • If you're trying to convince a Flat Earth Believer then you're out of luck. They are fixed points, immovable in their belief. You could fly one to the moon and show him the Earth and he would not believe that it was round. – Corey Oct 15 '18 at 10:25
  • You have to define "flat" first and agree on the definition. The obvious one is: a 2-dimensional Euclidean geometry (though we could allow for 1+1 Minkowski). In that case, the only legitimate test is whether the distances for the "straight lines" (i.e. geodesics) accord with Euclidean geometry. The simplest test: the 6 distances for any 4 points. If every 4 points make a flat tetrahedron, then the surface is flat. Otherwise, not. In fact, you can have 4 points whose distances don't even close into a tetrahedron in 2D, 3D or any-D! Example: Houston, Miami, Chicago, New York. – NinjaDarth Oct 11 '23 at 17:01

17 Answers17

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Simplest, you say? There are two that strike me as being simple to demonstrate. Luckily someone on the internet has already spent some time to help us here to make these easy to illustrate:

1. Shadows differ from place to place

Flat earth Curved earth

Eratosthenes carried out this experiment to determine the circumference of the Earth, already assuming its spherical shape; incidentally, the proof of such being consequential of the procedure.

However, a demonstration can be achieved by a simple, local experiment (as opposed to having a party venture to a distant enough point):

Take a piece of card (A3, or so), attach two obelisks to the card by their bases and, with a light source, produce shadows - now, slowly bend the card so that it becomes convex (that is, the side with obelisks attached bulging out) and watch the effect.

2. You can see farther from higher

Flat earth Curved earth

There are numerous other ways of demonstrating that the Earth is round, or curved, at least, from analysing the center of gravity to simply observing the other round objects that are visible in space; but I believe these illustrations to be the simplest to comprehend.

Images sourced from SmarterThanThat

Grant Thomas
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    #1 assumes that the sun is arbitrarily far away, and #2 can give conflicting results at long distances due to atmospheric refraction – Nick T Aug 05 '16 at 22:35
  • #2 is not true. The horizon always comes up to your eye level. So the distance you can see cannot be attributed to the higher you are up. – Java_User Jul 06 '17 at 13:40
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    @Java_User that'll only mean you're looking down. What if you try to look along your local horizontal, e.g. using a bubble level? You'll see that the horizon is a bit lower. And the higher you get, the lower the horizon appears to be. – Ruslan Oct 23 '17 at 06:54
  • #1 can't prove it with two points, but it can with three. Place an observer at the equator at noon on the equinox (sun directly overhead), and two other observers 1,000 and 2,000 miles north respectively. Have all three measure the angle to the sun at the same time. If the earth is a sphere, there is provably no solution that can be found for the measured angles that allows a flat earth and a relatively nearby sun. – dgnuff Oct 17 '18 at 21:20
  • With 4 points, you can prove a 2D surface is not flat - using the Flat Tetrahedron test. Their 6 distances give you a tetrahedron of volume 0. There's an even simpler test: they should also satisfy the 3D version of the triangle inequality. The distances for New York, Chicago, Houston and Miami don't! With 5 points and 10 distances, you can estimate the surface's curvature; e.g. add Los Angeles and you get 7902 miles diameter. But 6 points and 15 distances (e.g. add Seattle) can determine whether the curvature's really constant. For the Earth: it's not! The Earth's not a sphere. – NinjaDarth Oct 11 '23 at 17:07
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The shadow of the Earth on the Moon during an eclipse and the way masts of ships are still visible when the hulls are out of sight are the classical reasons.

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    actually, with a telescope or another telescopic sight, you can show the mast again. It's perspective. – Carlos Carlsen Feb 28 '17 at 17:41
  • @ sorry - poorly worded – Martin Beckett Feb 28 '17 at 20:33
  • let's say the mast is only visible (because of 'curvature'), what we could do is take a telescope and focus on the ship => The telescope would allow us to see the whole ship. We can't see the mast due to perspective, not a massive amount of curvature. It's perspective; Every art student knows that. – Carlos Carlsen Mar 01 '17 at 16:26
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    @CarlosCarlsen the telescope doesn't make your view line curved, you'll still only see the masts. Beware of mirages though: they can totally mess up the observations. – Ruslan Oct 23 '17 at 06:45
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    Funny that people are so strict affirming wrong things. Actually every student knows that no, you can't see around a corner. Perspective does not help. Perhaps meantime you mount and aim the telescope the ship got nearer :) – Alchimista Dec 14 '17 at 10:52
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    @CarlosCarlsen If what you say is true, than gradual zooming in on a ship partially below the horizon would gradually bring the ship up. And zooming out would submerge the ship back under the horizon. This could be recorded on a video. But I have never seen such a video. I have seen videos where flat-Earthers claim this is documented, but in all these videos there is just a ship still completely above the horizon, where zooming in and out only makes it smaller or bigger. No submerging/reappearing of the hull is happening. – mpv Oct 15 '18 at 13:38
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Another way is the triple-right triangle:

  1. You move in a straight line for a long enough distance
  2. Turn right 90° degrees, walk in that same direction for the same distance
  3. Turn again to the right 90° degrees and walk again the same distance

After this you'll end up at the starting point. This is not possible on a flat surface since you'd just be "drawing" an incomplete square.

enter image description here

Source: http://www.math.cornell.edu (add /~mec/tripleright.jpg to find the image)

Alenanno
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    "Walk"? At some point, you'll have to swim. :) Which might be a welcome change from a year of walking... – cHao Apr 04 '14 at 04:18
  • @cHao Or you can use a hot-air balloon. :D – Alenanno Apr 04 '14 at 09:28
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    What is the minimum distance for each side? – Fractional Apr 14 '14 at 15:43
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    @RedSirius I asked that very question some time ago. :) – Alenanno Apr 14 '14 at 17:17
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    What's a practical way to ensure one is both turning through exactly 90 degrees and proceeding in "straight" lines? – Todd Wilcox Feb 02 '16 at 18:50
  • @ToddWilcox With a goniometer and a ruler? :D Seriously though, with tools. For example, a plane would tell you if you're going straight and how much you turned. – Alenanno Feb 02 '16 at 18:52
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    A "plane"? Do you mean an airplane? I just realized that following the beam of a powerful enough laser would be pretty effective for moving in a straight line, if the source of the laser were elevated and the beam were split vertically to make sure it stays accessible from the ground level. – Todd Wilcox Feb 02 '16 at 18:55
  • @ToddWilcox Yes, an airplane. Doing this method by walking would be very time consuming and be generally more complicated/difficult. – Alenanno Feb 02 '16 at 18:58
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    I guess my question was how do you keep the airplane flying straight? They don't automatically move along a straight line. A flat-earther wouldn't accept bearing-keeping by magnetic compass as proof (the magenetic field of the earth could be "curved"), but might accept gyroscopic navigation. An airplane following a laser would do nicely if such a system could be devised. – Todd Wilcox Feb 02 '16 at 19:05
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    @ToddWilcox I don't fly airplanes, but I know they have instruments that tell you what coordinates you're following. And if flat-earthers were open to scientific demonstrations, there wouldn't be flat-earthers. The thing is that their answer is not derived by the available evidence, rather it's the opposite. – Alenanno Feb 02 '16 at 19:08
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    One thing I wonder is what is the minimum distance one would need to travel for this method work. – Skyler Jul 09 '17 at 23:30
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    @Skyler I asked that very same question. :) – Alenanno Jul 10 '17 at 05:50
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    3/4 finished square – dibs Oct 28 '17 at 08:51
  • @dibs ahah indeed, you're right. :D (Sorry, I've just seen that.) – Alenanno Jul 07 '18 at 09:35
  • Nobody's walking 10000 km from the equator to the North Pole. It would be much simpler to just stay in the same area. For that: you use 4 points, not 3; and you don't need to go far. For instance, you can prove non-Euclideanness without leaving the US. The 6 distances for New York, Miami, Houston and Chicago do not form a tetrahedron in ANY Euclidean geometry of ANY number of dimensions! Not 2D, nor 3D, etc. They fail the Tetrahedron Inequality, which is the 3D version of the Triangle Inequality. – NinjaDarth Oct 11 '23 at 17:15
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If the person in question is from a temperate latitude, take them to the tropics to feel the heat of the noon sun, preferably trapped out on a sailboat without water. Point to the very high sun and make your point when they are the most miserable. Next, take them to a very high latitude. As they freeze and become exhausted at 3:00 AM while out walking the tundra, point out the low, non-setting (or non-rising) sun, and re-iterate your point in their heightened state of misery. Through suffering and a sense of pride, the object of your demonstration will now likely feel that they have "been there" and "seen it" with "their own eyes". If convinced, that person will gladly proselytize the "truth" of aforementioned roundness of said planet, and will confront the heretics who do not believe.

I think that there are no simple answers to provide "proof" of anything. "Proof" is relative, much in the way "truth" is relative. If simple means "without using science or technology" then you are without hope, as the receiver of the "proof" must accept the truth of the methodology.

Photos from space are photoshopped.

Ships at sea look below the horizon because Osirus/Neptune/Odin/Jesus/Bhaal does not wish man to see to infinity (which also proves that the heavenly bodies are not very far away).

Sticks in the dirt and shadows prove nothing unless you accept that other bodies are permanent, in orbital motion, and far away (at which point the person will already believe that the planet is round).

Don't try to prove anything. You can't. Instead, "Demonstrate and educate", because all you can do is convince, not prove.

  • +1, the power of 'torture' ? ;) Fernão de Magalhães paid with is life to prove that the Earth is round. (in eng. is Ferdinand Magellan) – Helder Velez Jun 28 '11 at 02:01
  • Proof also connotes finality. Once something is proven, it need never be considered again. –  Feb 20 '13 at 15:32
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    @HelderVelez no he did not. People already knew the earth was round back in his time. He was hired to gather evidence that some people were invading some other people's territory on the pacific, by measuring the coordinates of said territory. He died because he picked a fight he shouldn't have, for stupid reasons, and took an arrow to his chest, not for saying what everybody already knew to be true. His story, as written by Pigaffeta, is interesting enough, but as others have said the ancient greek already know about the curvature of our planet. – Thermo's Second Law Mar 27 '17 at 13:18
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Sitting for a while by the seashore ought to make it clear the Earth isn't flat, even if you don't happen to see a ship go over the horizon. The edge of the discworld Earth would have to be just a few miles away, and there's no way that the entire, circular world would fit inside the circle that the ocean horizon seems to make.

Humans have not just known the Earth was spherical but actually have been measuring its radius for thousands of years. http://en.m.wikipedia.org/wiki/History_of_geodesy

Andrew
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Besides the going back in time option, you could just show your "numbskull cousin" a picture of the Earth taken from the moon like the one below.

Gif

  • Like the approach, side stepping an academic approach. Also you could show them picture/video from the ISS or this great video of James May taking a trip in a U2 spy plane where you can clearly make out that the Earth is round from 13 miles up: http://www.youtube.com/watch?v=x6cZLfK4Zjk – Fergal Jun 27 '11 at 11:22
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    I just find that sometimes when you are going for "simplest way", you have to tailor it to the audience. Some audience members aren't going to understand the math or the academic approach and a different way to show them is necessary. – Annika Peterson Jun 27 '11 at 16:23
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    What if your "numbskull cousin" doesn't believe in the moon landing? It's all fake! – jkeuhlen Dec 24 '14 at 20:53
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    That photo wasn't actually taken from the moon, it was taken by Apollo 17 while on its way to the moon -- about 5 hours from launch - 2 hours after leaving Earth's orbit on the way to the moon. Though there are plenty of spectacular photos of the Earth from the Moon, plus some of moon and earth taken from beyond the moon – Johnny Oct 26 '16 at 20:42
  • Funny. From moon? Answer this simple question. Does thrust works in vacuum? If not then how do people land on Moon? – Java_User Jul 06 '17 at 13:43
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    @Java_User why should thrust depend on an atmosphere? Newton's third law posits that "For every action, there is an equal and opposite reaction." So all you have to do to produce thrust is to throw mass in the direction opposite to the direction you want to go. You can test this by throwing stones from a small boat on a quiet lake. – Georg Patscheider Oct 18 '18 at 15:25
  • What do you mean? That is obviously a picture of a disk. /s – Christopher King Mar 05 '19 at 08:12
  • Optics is not a legitimate argument. For instance, the surface comprising the event horizon of a black hole appears flat at the right distances from it, and even hyperbolic if you get closer. What's being tested for is intrinsic curvature - and any appeal to extrinsic anything is an automatic out. – NinjaDarth Oct 11 '23 at 17:18
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Classically, the gravitational force experienced by a mass $m$ above the Earth is given by the familiar,

$$F=G\frac{Mm}{r^2}$$

where $M$ is the mass of the Earth. In other words, a mass will experience a force which continually decreases as it distances itself away from the Earth. Now suppose the Earth was a flat infinitely$^{\dagger}$ large plane in $\mathbb R^3$ which is infinitesimal, with mass density $\sigma$ (per unit area, not volume). The gravitational potential $\Phi$ satisfies the Poisson equation $\nabla^2 \Phi = 2\pi G \sigma \delta(z)$, assuming the plane is at $z=0$.

enter image description here

The solution is given by $\Phi(z)= 2\pi G \sigma |z|$. The gravitational force is $-\partial_z \Phi$, which is always pointing towards the plane. Another feature is that the gravitational force is constant with magnitude $2\pi G \sigma$. In other words, no matter how high one is above the plane, the same forced is experienced. To be more realistic, if the plane had some non-zero thickness, the force would still be constant, but whilst inside there would be a 'jump' as depicted:

enter image description here

Hence, to determine if the Earth is flat, one would simply have to conduct an experiment to see how the gravitational force scales as one increases altitude. One will find $F \sim r^{-2}$ approximately, as expected, confirming the Earth is round. Of course, for sufficiently small variations in $r$, one may be fooled into thinking $F$ is constant since the change is minute, but it is measurable.


$\dagger$ For convenience, it is taken to be infinitely large; the conclusions remain the same, but the force will of course be different, since it will be dependent on $x$ and $y$ as well.

JamalS
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    I like this answer because it is one the knowledge - impaired cousin can easily understand – WoJ Dec 22 '15 at 06:21
  • @WoJ In case you hadn't realised, people other than the OP read the answers on a question and so an answer can be for a broader audience... Imagine that? – JamalS Apr 04 '22 at 02:18
  • Yes, I imagine that and this is why I upvoted your answer. Relax. OP wanted a bare-bones answer which can be understood by primitive tribes. I am glad that expect them to understand that. – WoJ Apr 04 '22 at 07:32
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You can build a simple pendulum and observe how it rotates as the day progresses. You can then put a pendulum on a stick or something that you can rotate yourself in order to demonstrate that when you rotate the stick, the pendulum will continue to swing in the same direction. This shows that the direction of movement of the pendulum will change relative to its base only if its base is rotated.

Pendulums can also be used to measure your latitude (its direction will change at different rates for different latitudes), and to measure the local value of g (the amount of time it takes to go through one cycle, or its period of oscillation, will vary with gravity).

Carson Myers
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    Doesn' t this merely prove the Earth rotates? – Andrew Jun 24 '11 at 10:21
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    @Andrew D'oh! I'm tired and assumed they meant the same. I guess by extension it proves the earth is round, assuming you're not doing this experiment at one of the poles. – Carson Myers Jun 24 '11 at 11:04
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    It's also surprisingly hard to build a decent Foucault pendulum. It is necessary to insure that the suspension is torque-free, which is not easy. – dmckee --- ex-moderator kitten Feb 26 '12 at 22:45
  • @dmckee torsion-free suspension is only part of the problem. I have seen the experiments described here from close up. Sir Brian Pippard was arguably a very, very good experimental physicist... but he was stumped. Well - he made a great pendulum, just not great enough to look for confirmation of the Thirring-Lense effect – Floris Jan 27 '16 at 20:49
  • The law of motion do not determine whether a surface is a flat Euclidean geometry or not. At best, it can only provide circumstantial evidence on the grounds that it's easier to explain the comparisons of the motion at different places as arising from the rotation of a non-Euclidean surface. But it's not a direct test - which can only be done by measure distances, since curvature is determined by the affine connection of the surface, and that (in turn), in the case of Levi-Civita connections, by the metric - i.e. by distance relations. – NinjaDarth Oct 11 '23 at 17:22
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The occurrence of noon (i.e. meridian passage of true Sun) isn't simultaneous for two observers situated along an east-west line. Hmmm...okay perhaps even simpler. Sunrise and sunset aren't simultaneous for those two observers.

  • The flat-earthers come up with some interesting depictions of how a "local sun" lights the earth - but I don't think any of those theories can coexist with our current observations of when and where sunset occurs. – JD Smith Jan 19 '24 at 21:29
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There's a video on youtube of a island a few miles away such that when you see the island from an elevation, you can see further to its base than you can when you see the island from the shoreline ( a demonstration of answer 1 above). I think this is the simplest way given that now we have zoom ability, anyone can do this kind of experiment on a clear day from any shoreline viewing something a few miles away.

http://www.youtube.com/watch?v=bco_p4V7-QU&feature=related

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I think the simplest way is to have two sticks of same size put both of them perpendicular to the surface of the earth in the mid day sunshine and the gape between them is to be few miles and exact time mesure the angle of elevation or mesure the size of the shadow so both will be differ! By several exams in a sysmetic order we can find that the earth is round.

4

If you're in the northern hemisphere, walk to the south and notice how Polaris sinks lower and lower each night until it disappears below the horizon. If he can handle more info point out how the stars before you are getting higher and the stars behind you are getting lower. Of course then you'll need to explain their east to west motions too.

Lambda
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Here's another way, which only works in the Southern hemisphere - at least that is the case if you use the Flat Earth Society's map of the world, where Antarctica is a ring of ice around the works, and the North Pole is at the centre.

When flying from Sydney to Santiago or Pretoria, you regularly get close enough to Antarctica to see it. If the earth were flat, that would mean a huge waste of fuel. Only on a spherical world does this kind of trajectory make sense. On a flat earth, the shortest distance from Sydney to Santiago is via the North Pole, Sydney to Pretoria takes you across the Himalayas.

Of course this depends on airlines trying to save fuel - if all of them are in cahoots with NASA and all the other conspirators who claim a spherical earth, then all bets are off...

hdhondt
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    Having been through a discussion in a radio show with a FE'er, I can tell you that this argument — as well as any other argument — does not prove anything to them. The extra fuel spent is nothing compared to all the resources outside the Southern Ring of Ice that are being hidden from us. – pela Jul 07 '18 at 11:11
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I am adding this answer because I feel like the other answer did not mention one aspect where we can very easily prove that the Earth is round (not flat), and it is doable with the naked eye, and no equipment is necessary.

enter image description here

I took this image myself, in a day of time where the moon is on the left (a little bit higher in the sky then the Sun), and the Sun is on the right, close to setting.

enter image description here

However, if you look at the image of the moon, it look like it is being lit from above a little bit, despite the Sun being much lower in the sky (relative to the Moon). It looks almost like the light is making a curved path across the sky as it propagates from the Sun to the Moon.

In reality this is caused by a lensing effect, and the curvature of Earth, and the curvature of the horizon (and the atmosphere). This is only possible if the Earth is round (not flat).

  • Do you have a reference for this effect? Are referring to atmospheric refraction? https://en.wikipedia.org/wiki/Atmospheric_refraction – Quillo Oct 04 '23 at 07:28
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  1. Watch live ISS footage. Neither Hollywood nor any software can produce this raw footage at such level of realism.

  2. See planes flying live. See for instance how you can go from NY to London, then from London to Tokyo, and the from Tokyo to NY, always going eastwards. If still in doubt, try it yourself.

0

Showing a picture of the earth from space seems like the simplest way to prove that the earth is round, but first of all you would need to convince this tribesman that this photograph is taken from far up in the sky. This can be done by taking a video of the earth from takeoff to orbiting the earth. That way he can see the connection between the world around him and the blue dot on a black background as representing the same thing, the earth.

Mozibur Ullah
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Seeing a plane disappear behind the horizon. If the earth wasn't round (i.e. flat) the plane would be visible for a longer time than if it was round, assuming it would be visible for a long time.
Of course, the earth could also have another, more exotic form, like a banana, kiwi, pear, or pine apple. Or maybe have a book form. So you have to make a distinction between two forms only: sphere-like or flat.