No, there is no general way to obtain simultaneously (e.g., by means of simple matrix operations) all possible driving point ("equivalent") resistances of a resistive network.
In general, the driving point resistance of a resistive network is given by the ratio of two determinants. One determinant depends only on the network and not on which resistance you want to determine. The second determinant is a suitable cofactor of the first one, and depends on the nodes across which you want to find the driving point resistances.
This means that if you have a network with $N$ nodes, you have to determine $\binom{N}{2}$ possibly different determinants (some can be equal due to symmetries).
If, instead, you want to consider only the equivalent resistances that can be found by fixing one of the nodes, as in the example you gave, this can be done easily through matrix inversion.
For more on these topics, you can have a look at:
[1] N. Balabanian, T. A. Bickart, Electrical network theory, Chapter 3, John Wiley & Sons, Inc., 1969.
[2] W.-K. Chen, Active network analysis, Chapter 2, World scientific, 1991.
[3] H. W. Bode, Network Analysis and Feedback Amplifier Design, Chapter 1, D. Van Nostrand, 1945.