0

The metric of the Poincare-AdS$_3$ geometry is given in the Wikipedia article on the Poincare coordinates of AdS$_3$ geometry:

$$ds^{2} = \alpha^{2}\left(\frac{du^{2}}{u^{2}} + u^{2}g_{\alpha\beta}dx^{\alpha}dx^{\beta}\right),$$

where $\alpha$ is supposedly the AdS$_3$ radius.


It appears that $0 < r < \infty$, in which the Poincare-AdS$_3$ geometry is not a cylinder.

But isn't the Poincare-AdS$_3$ geometry a cylinder? Where have I gone wrong in my thinking?

nightmarish
  • 3,183
  • According to the Wiki-page you linked, "...where $\alpha$ is a nonzero constant with dimensions of length (the radius of curvature)" and "Topologically, anti-de Sitter is $S^1 \times \mathbb R^{nāˆ’1}$". (under the section Definition and Properties) – ersbygre1 Oct 08 '17 at 23:12
  • So, this geometry indeed has $r$ ranging from 0 to $\infty$? – nightmarish Oct 08 '17 at 23:15
  • I'd say so, but I'm no expert... – ersbygre1 Oct 08 '17 at 23:20

0 Answers0