As teflon has a minimal frictional coefficient of about 0.04, how far does a ball made of teflon roll on a even surface in comparison to another ball (made of wood or iron, for example), when pushed by a specific force?
Edit: The surface is solid and not that much deformable, such as wood.
Coefficient of friction describes the behaviour of sliding one surface over another, it's important to use the (generally much lower) co-efficient of rolling resistance.
All other things being equal in the comparison, and as a result of how it is defined, the retarding force is proportional to the coefficient of rolling friction. Since work = force x distance, to do the work necessary to bring the ball to a halt (to cancel its kinetic energy including that due to rotation) is given by d=w/f. Distance is therefore inversely proportional to co-efficient of resistance.
The comparitive equation is thus
$$\frac{d_1}{d_2}=\frac{c_2}{c_1}$$
d=distance, c=coefficient of rolling resistance.
Note: The following must be equal to cancel out in the comparison: rigidity of ball and surface, initial kinetic energy (as supplied by the initial force). Air resistance and any other retarding forces. force due to gravity.
Thus if you now choose a material to compare Teflon too, and you know their rolling resistances on the surface used, you could predict the answer. I couldn't find such specific figures, but there are some examples of real world rolling resistances here. I suppose to try to select similar materials, the steel bearing is a low value rolling resistance, objects have to be specially designed to have 100 times that value.
So I estimate the answer you want might be very aproximately "The teflon ball will roll an order of magnitude (10x) further."
