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Imagine there is a train in front of me and I'm on a train following behind pushing with a force of 100 Newtons for one minute. I can't imagine getting twice as tired if the train is moving a 40km/h instead of 20km/h. The only solution I can see is that some of the work the train is doing must be getting included as well. This creates an obvious question - exactly what work is the work that is included here?

Notes:

This question is similar to this one, but is different because in my question I am actually doing steady work by continuing to push on the front train.

Dale
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Casebash
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    This seems to essentially be a duplicate of https://physics.stackexchange.com/q/1984/50583 – ACuriousMind Mar 29 '20 at 13:08
  • @ACuriousMind Not quite because of the second part – Casebash Mar 29 '20 at 13:09
  • Please ask only 1 question per post. – Qmechanic Mar 29 '20 at 13:30
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  • If the first part is answered by the duplicate please edit your question to remove it. 2. It is not clear to me how the second part is meaningfully different - in the first case your tiredness is not related to any mechanical work done at all (since there is no mechanical work done!). Why would you expect it to be different in the second case?
  • – ACuriousMind Mar 29 '20 at 13:30
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    @ACuriousMind Edited. In the second case you are doing work – Casebash Mar 29 '20 at 13:34
  • What are you pushing on in the second example? – Bob D Mar 29 '20 at 13:43