Background
left: from this answer to Moon during the day with bright blue sky light right: from Why does Unity look transparent? below: from this answer
note Unity is the bit in the middle.
I'm trying to estimate roughly how much of the sky's diffuse blue light is produced between us and this very high altitude object.
Question
Answers to Where in the atmosphere is the blue light scattered? don't provide a quantitative answer to the question's title so I thought I would try to estimate the contribution to the blue light we see at sea level from each altitude.
I started with a simplistic approximation for the density profile using a scale height $H$ of 8.5 km. Using pressure as a proxy for density assumes constant temperature and composition so it's only a starting point.
$$\rho(h) \approx \exp(-h/H)$$
Next is the Rayleigh scattering. Wikipedia gives the following for a volume of dielectric spheres of index $n$, diameter $d$ and a distance $R$:
$$I_{0}{\frac {1+\cos ^{2}\theta }{2R^{2}}\left({\frac {2\pi }{\lambda }}\right)^{4}\left({\frac {n^{2}-1}{n^{2}+2}}\right)^{2}\left({\frac {d}{2}}\right)^{6}},$$
and for a certain region of volume $V$ of the atmosphere:
$$I_{0}{\frac {\pi ^{2}V^{2}\sigma _{\epsilon }^{2}}{2\lambda ^{4}R^{2}}}{\left(1+\cos ^{2}\theta \right)}$$
where $\sigma_{\epsilon}^{2}$ "represents the variance of the fluctuation in the dielectric constant $\epsilon$.
The Wikipedia article's reference #18 links to
McQuarrie, Donald A. (Donald Allan) (2000). Statistical mechanics. Sausalito, Calif.: University Science Books. pp. 62. ISBN 1891389157. OCLC 43370175.
and on page 63:
This is called Rayleigh scattering. The dielectric constant $\epsilon$ is related to the density by the so-called Clausius-Mossoti equation
$$\frac{\epsilon-1}{\epsilon+2} = A \rho$$
which is derived and discussed in most physical chemistry texts. The quantity A is a constant and $\rho$ is the density. We can see from this equation that fluctuations in $\rho$ lead to fluctuations in $\epsilon$, and hence to Rayeligh scattering by Eq. (3-56). If we calculate $\sigma_{\epsilon}^{2}$ n terms of $\sigma_{p}^{2}$ from Eq. (3-57) and use Eq. (3-54) for $\sigma_{p}^{2}$, we can find (see Problem 3-21)
$$\frac{I(\theta)}{I_0} = \frac{\pi k T}{18 \lambda^4} \kappa (\epsilon-1)^2(\epsilon+2)^2 V \frac{1+cos^2 \theta}{R^2}$$
where $\kappa$ is the isothermal compressibility...
One hopes to somehow express $(\epsilon-1)^2(\epsilon+2)^2$ in terms of $\rho$ using the relations above, but I don't know how to address the isothermal compressibility $\kappa$ as a function of height.
The $V/R^2$ cancels in the same way that a diffuse wall doesn't appear to get brighter nor darker as we walk away from it.
Question: How much of the sky's "blue" comes from each altitude; how can I get the variation of the atmosphere's dielectric constant and isothermal compressibility in order to estimate this?

