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The top answer to Is there an equation for the strong nuclear force? explains that there is a coulomb's law-like formula:

$V(r)=−\frac{4}{3}\frac{α_s(r)ℏc}{r}+kr$

that describes how quarks and antiquarks interact with each other. The author points out that the $\alpha_s$ factor is dependent on the distance between quarks, so what is that dependency? What is $\alpha_s$ as a function of r?

Cosmas Zachos
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eaeaa1232
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1 Answers1

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The phenomenological potential you wrote is closest to the Richardson 1979 potential loosely inspired by one gluon exchange, where $\alpha_s$ decreases logarithmically with distance for small r, $$ \alpha_s \propto \frac{1}{\ln (1/r^2\Lambda^2)} $$ Λ being the QCD scale of ~200MeV or so.

Such potentials, including confinement linear terms and more functions with more adjustable parameters can be found in reviews, eqn (15a), such as A. Bykov, Dremin, & Leonidov (1984) Usp Fiz Nauk 143 321 ...

Cosmas Zachos
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