A black hole has a radius of $R = \frac {2Gm}{c^2}$, in this context, if we take a single proton and neutron as a black hole, its Schwarzschild radius will be near about $4.8 \times 10^{-52} \mathrm{m}$.
Now quantum mechanics says that both particles can stay together if they satisfy the uncertainty relation as $$\Delta P \Delta R \geq \hbar$$ by taking mass as the mass of the proton and space as the Schwarzschild radius; this uncertainty relation is definitely violated.
However, in this scenario, a black hole is not consistent with the quantum theory. Please answer my question.
Your equation just implies "a proton with a relativistic uncertainty will not be localized well enough for it to be inside a black hole". With this particular uncertainty, it won't be in a black hole. The first commenter is right; nobody believes black holes and quantum mechanics are fully compatible, but this isn't actually a contradiction.
– AXensen Mar 21 '23 at 14:27