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I learn something about the Time evolution of Gaussian wave packet in free space. if the initial condition is a Dirac delta function at $t=0$, then the wave function is $$ \psi (x,t)=\frac{1}{\sqrt{2\pi it}}e^{-\frac{x^2}{2it}} $$

my question is it seems that the square of the modulus of

$$ \left |\psi (x,t) \right |^{2}=\frac{1}{{2\pi t}} $$

which has nothing to do with the independent variable x, I can not understand the result.

Your help would be highly appreciated!

Qmechanic
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    here you can find answers to your question... https://physics.stackexchange.com/q/334574/362609 – pabloealvarez Apr 17 '23 at 15:39
  • A free particle will instantaneously spread out equally over all space if its initial state is a delta function. – march Apr 17 '23 at 15:52

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