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I have three doubts regarding the magnetic field due to the charge:-

  1. Is a magnetic field generated when a charged particle moves with constant velocity or it only generated when the charge particle is accelerated or both?
  2. Why and how does movement of charge result in the creation of a magnetic field around the particle?
  3. We also know that motion is relative so if we observe in frame of moving charged particle then its magnetic field should not be there, then what we do in this case?
    Note (related to third question): as we use pseudo force in non-inertial frame then what do we use in this case?
Qmechanic
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ayu
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3 Answers3

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  1. The magnetic field is induced if the charge's velocity is non-zero. It doesn't matter whether the acceleration is zero or not.
  2. As far as I know, there is no explanation for the why question, just a mathematical description of the process (Ampère's law, or, more generally, the Maxwell equations).
  3. Yes, in the comoving frame there is no magnetic field, only the electric field. So the magnetic field strength is indeed frame dependent.
Photon
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  • we don't have answer of 2nd ques in our modern physics ? – ayu Aug 07 '23 at 14:44
  • @ayu : please search a bit on PSE. I remember a recent post where an experienced physicist explained that the Maxwell equations don't say what is causing what. These equations relate $E,B$ fields charges and currents with each other. That's it. – Kurt G. Aug 07 '23 at 14:46
  • what is PSE? ohh by the way thanks for explaining – ayu Aug 07 '23 at 14:48
  • Physics Stack Exchange is PSE. ;) – Photon Aug 07 '23 at 15:11
  • Re 1) acceleration sometimes matter. Non-zero magnetic field does not require that the charge is moving or was moving with non-zero velocity at the time of production. Radiation component of electric field of a charged particle $\mathbf E_r$ is proportional to charge's acceleration, and in the first approximation, independent of velocity, so it is present/generated even if velocity is zero. Since radiation component of magnetic field is proportional to $\mathbf n \times \mathbf E_r$, the same is true for magnetic field. – Ján Lalinský Aug 08 '23 at 02:14