At low photon energies, the probability of the photoelectric effect to occur increases, but the probability of the photoelectric effect to happen also increases when going towards most inner shells like K shell but inner shells require much more photon energies to be broken, so isn't there a contrast here? How is this EVEN possible?
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I think the answers here are adequate https://physics.stackexchange.com/questions/206263/why-is-the-k-shell-electron-preferred-in-the-photo-electric-effect , – anna v Sep 28 '23 at 03:09