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Maxwell said that charged particles radiate when are in accelarating motion. I understand that $nλ=2πr$ must be fulfilled in order to create a sinusoidal standing wave and to satisfy the probability distribution problem, but I don't have any clue why electron doesn't radiate in this case !

Qmechanic
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cheesebread
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  • You've tagged this question with 'quantization'. Think about that for a bit (specifically, photons as quanta). Does that help you to understand why the electron cannot radiate (once it's in the ground state)? – tok3rat0r Jun 30 '15 at 09:26
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    Hi Sam. This question has been asked already lots of times. I've linked the duplicate that seems most popular. – John Rennie Jun 30 '15 at 09:31
  • There is no reason to believe that electrons do orbit the nucleus, Bhor's model is just approximately correct and you need Schroedinger's equation to really solve the problem of a single electron atom. And even that equation is only valid in the non-relativistic limits. – iharob Jun 30 '15 at 12:34
  • So nucleus is actually a node for electron(or the standing wave) ? like for f+3 f-3 if electron changes it bubble(like in Dale's image) nucleus will be on electron's path and that point will be a node or electrons cant change bubbles ? (I dont know if this question means anything or not :p I am trying to understand orbitals better . . .) – cheesebread Jul 03 '15 at 07:59

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