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Is it really true that focusing EM-waves of the same frequency, intensity, energetic density, on the same spot, we can rise temperature on that point indefinitely? I read there is a limit. Thanks.

-EDIT-: This solved my doubt because now I know formulas that simplify the understanding of how Power and Energy are linked in a luminous system...

mpv
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2 Answers2

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The temperature of an object depends on the rate that heat is being added to the object and the heat that the object is losing heat to its surroundings. If you have some object at a temperature $T$ then the rate of heat loss is given by:

$$ W = kT + \sigma T^4 $$

where the first term on the right comes from Newton's law of cooling and the second term from the Stefan-Boltzmann law.

The maximum temperature of the object will be when the power radiated is equal to the power being supplied, so if the EM waves you are directing on the object have a power $P$ the maximum temperature is given by solving the equation:

$$ P = kT + \sigma T^4 $$

At very high temperatures the radiative cooling will dominate and the equation simplifies to the approximate equation:

$$ P \approx \sigma T^4 $$

or:

$$ T \approx \sqrt[4]{\frac{P}{\sigma}} $$

So, no, the temperature won't rise indefinitely. It will reach a maximum value given by the equation above.

John Rennie
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  1. The temperature of a body depends from the motion or vibration of the subatomic particles. Could you accelerate a subatomic particle to a greater velocity than the speed of light?

  2. Not having any particle inside an area and shining photons of whatever intensity into this vacuum could one speak about a temperature at all?

  3. Having a single subatomic particle in an area and fokusing intensive enough photons on this position wouldn't take place a particle creation?

It would be interesting if where are more reasons why it isn't possible to reach infinite temperature.

HolgerFiedler
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  • I belive it is geometrically realiable to focus more than 4Pi Stereorad of light from "one" source at a same temperature. In this case the temperature of the point will rise over the source temperature? – Gabriele Citossi Sep 11 '17 at 12:26
  • Your first point is completely incorrect. A particle's energy can increase without bound even with its velocity bounded by $c$. – Emilio Pisanty Sep 11 '17 at 13:25
  • @Emilio How this is possible? – HolgerFiedler Sep 11 '17 at 15:52
  • Because relativistic kinetic energy is not a quadratic function of velocity. See any introductory textbook on special relativity, or indeed the relevant sections of Wikipedia, for further details - ideally before posting more misinformation on the site. – Emilio Pisanty Sep 11 '17 at 16:50
  • @EmilioPisanty So the temperature of a subatomic particles does not depends from its motion (in a gas in some closed volume as well as vibrational in a rigid body)? – HolgerFiedler Sep 11 '17 at 18:24
  • No. Read my comments again. – Emilio Pisanty Sep 11 '17 at 19:09
  • @EmilioPisanty "a simplified description of fluid matter, temperature is proportional to the average kinetic energy of the random microscopic motions of the constituent microscopic particles, such as electrons, atoms, and molecules, but rigorous descriptions must include all quantum states of matter." From https://en.wikipedia.org/wiki/Temperature – HolgerFiedler Sep 11 '17 at 20:03
  • Your first bullet point makes the claim that the kinetic energy of a massive particle is bounded because its velocity is bounded; that is incorrect and little more than misinformation. (The rest of your claims are irrelevant to the question but they're not incorrect.) In uninterested in further discussion. – Emilio Pisanty Sep 12 '17 at 00:37