$\def\br{{\bf r}} \def\bF{{\bf F}}$
Consider the following system. Two particles, equal masses, no
external forces. Force acting on particle #1 (due to particle #2):
$$\bF_1 = k_1 (\br_2 - \br_1).$$
Force acting on particle #2 (due to particle #1):
$$\bF_2 = k_2 (\br_1 - \br_2).$$
You can verify that this system satisfies
- isotropy of space (each force is always directed towards the other particle)
- homogeneity of space (a translation of system leaves forces
invariant)
- homogemeity of time (forces do no depend on time).
Yet Newton's third law isn't satisfied if $k_1\ne k_2$. Total momentum isn't conserved, com is accelerated...
How can it be? The point is that @AbhimanyuPallaviSudhir is wrong:
conservation of momentum is not equivalent to translational
invariance. Or, to be more precise: it's not equivalent to
translation invariance of forces - invariance of Lagrangian is
required. Only if there is an invariant Lagrangian Noether's theorem can be proven.
But the system I defined admits of no Lagrangian. Actually its forces don't derive from a potential.
But, for example, in the case of electromagnetic interaction there is no Newton third law and you need to consider the momentum of the field to have conservation of momentum.
In the most general case of position and velocity dependent forces, what can be said about the forces if we assume homogenity and isotropy of space?
– AndresB Mar 30 '19 at 13:29