Let us denote the half-life of the proton by $Y_p$. (There is, of course, no experimental evidence that $Y_p<\infty$, but there are theories that assert it, so this is really a question about those theories).
The question is: what, in that case, is $Y_C$, the half-life of a carbon-12 nucleus?
A naive answer would be that since $^{12}C$ contains six protons, $Y_C=\frac{1}{6}Y_p$.
However, protons do not decay. Quarks do. Since neutrons are made of as many quarks as protons are, they should decay into non-baryons just like protons. Since $^{12}C$ contains twelve nucleons, that makes $Y_C=\frac{1}{12}Y_p$.
- Which is it? $\frac{1}{6}Y_p$ or $\frac{1}{12}Y_p$?
There is a hidden assumption in all this: that the half-life of a quark is unaffected by the baryon or meson in which it finds itself. On the other hand, the half-life of a neutron is strongly affected by the nucleus in which it finds itself (or doesn't).
- Is the assumption of environment-independence correct for the decay of quarks into leptons?
There is one more assumption. Protons and neutrons are each made of two different kinds of quarks.
- Do the theories that make quarks decay into leptons assign identical half-lives for this process for both up quarks and down quarks?