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After constructing a physical state and discovering the particle content, how can one find the fermionic and bosonic degrees of freedom?

Eg.

Constructing the physical states of an $\mathcal{N} = 2$ short massive vector multiplet, with $s = \frac{1}{2}$ we get:

$$\left( -1, 2 \times \left(-\frac{1}{2}\right), 2 \times 0 , 2 \times \frac{1}{2} ,1\right)$$

From this I can see the particle content:

$(-1,0,1) \to 1$ massive vector

$\left( 2\times \left( -\frac{1}{2}\right),0,1 \right) \to 1$ massive Dirac Fermion

$(0) \to 1$ massive real scalar

How do I calculate the bosonic and fermionic degrees of freedom based on the helicity content?

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    Related: https://physics.stackexchange.com/q/100995/2451 – Qmechanic Apr 12 '20 at 17:39
  • That is very helpful but it doesn't say anything about fermionic or bosonic d.o.f. , it only mentions general d.o.f.. Is it the same thing? Or is there a relation?

    Thank you so much for your help

     –  Apr 12 '20 at 17:54
  • The answer depends on spin rather than fermions/bosons (although this is of course related cf. the spin-statistics theorem.) – Qmechanic Apr 13 '20 at 11:23

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